3 years ago

Anybody know the answer to these

Mathematics

1 answer:

ra1l [238]3 years ago

5 0

M= -3
K=-5
X=3.1
There are the first 3 answers

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There are 9 classes of 25 students each 4 teachers in two times as many chaperones as teachers each bus hold a total of 45 peopl

Tanya [424]

Answer:

Least number of bus require for trip = 5 buses (Approx)

Step-by-step explanation:

Given:

Total number of classes = 9

Number of student in each class = 25

Number of teacher = 4

Number of chaperones = Double of teacher

Bus hold = 45 people

Find:

Least number of bus require for trip

Computation:

Total number of student = 9 × 25

Total number of student = 225

Number of chaperones = 4 × 2

Number of chaperones = 8

Total people = 225 + 8 + 4

Total people = 237

Least number of bus require for trip = Total people / Bus hold

Least number of bus require for trip = 237 / 45

Least number of bus require for trip = 5.266

Least number of bus require for trip = 5 buses (Approx)

6 0

3 years ago

If x-1/x=5 find x^3+1/x^3=?

ipn [44]

$\dfrac{x-1}{x}=5\ \ \ \ /x\neq0\\\\\dfrac{x-1}{x}=\dfrac{5}{1}\ \ \ \ |\text{cross multiply}\\\\5x=x-1\ \ \ \ |-x\\\\5x=1\ \ \ \ |:5\\\\x=0.2\\\\\dfrac{x^3+1}{x^3}=\dfrac{x^3}{x^3}+\dfrac{1}{x^3}=1+\dfrac{1}{x^3}\to1+\dfrac{1}{0.2^3}=1+\dfrac{1}{0.008}\\\\=1+\dfrac{1}{\frac{8}{1,000}}=1+\dfrac{1,000}{8}=1+125=126\\\\\text{Answer:}\ \dfrac{x^3+1}{x^3}=126$