23x^3 - 5x^2+12x-1
I think.. I’m not positive though.. I hope this helps!
Answer:
Yes, that's correct.
Step-by-step explanation:
Answer:
(B) 0.42=0.420
PLEASE MARK ME AS BRAINLIEST....
<span>N(100, 16) means a normally distributed population with a mean of 100 and a standard deviation of 16.
Using the 95% confidence level factor (1-tail), which is approximately 1.65, then, any IQ that exceeds:
100 + 16*1.65 is higher than 95% of the population. I'd consider that unusually high.</span>