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lyudmila [28]
3 years ago
13

Sarah invested $2,500 in an account paying an interest rate of 2.1% compounded continuously. Assuming no deposits or withdrawals

are made, how much money, to the nearest hundred dollars, would be in the account after 14 years?
​
Mathematics
1 answer:
marysya [2.9K]3 years ago
3 0

Answer:

sorry 2458946547165874%

Step-by-step explanation:

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Please help,I need it for tomorrow​
Inga [223]

Answer:

<C=26

<B=48

<D=106

<F=42

Step-by-step explanation:

I labeled all the angles to help this make more sense :)

So first we find <C, which is supplementary to <E so just do 180-154=26

Next, we know that <F and <B are equal because they form corresponding angles.

Angles <C <D and <B form a triangle. The three angles of a triangle always equal 180. Now that we know angles <C and <B, we just do 180-26-48=106.

Lastly, to find angle A, we just take 180-106-48=42.

Hope this helps

7 0
2 years ago
Find the common difference in the outputs to help find the missing outputs in the table
WINSTONCH [101]

Answer:

if you are trying to find the rest of A it would be adding by 1 because of the slope so: 5,6,7,8,9,10. The slope of B wouldbe .8 because it is increasing by .8 everytime so: 3.8,4.6,5.4,6.2,7.0

Step-by-step explanation:

B) 4.6-3.8= .8

5.4-4.6= .8

slope is .8

5.4+.8=6.2

6.2+ .8= 7.0


8 0
3 years ago
Read 2 more answers
Which ratio is equivalent to 4:5?
maw [93]

Answer:

8:10 and 12: 15

Step-by-step explanation:

we have to multiply

5 0
3 years ago
the sum of three numbers is 11. if you triple the second number and add the third number, the result will be equal to the first
leonid [27]
<span>1st number = 11, 2nd number = 5.5, 3rd number = -5.5</span>
3 0
3 years ago
Simplify each only using positive exponents:<br> 2x^-3 • 4x^2<br> 2x^4 • 4x^-3<br> 2x^3y^-3 • 2x
erica [24]
<h2>Answer:</h2>

\frac{2}{x}

\frac{x}{2}

\frac{4x^4}{y^3}

<h2>Step-by-step explanation:</h2>

a. 2x^-3 • 4x^2

To solve this using only positive exponents, follow these steps:

i. Rewrite the expression in a clearer form

2x⁻³ . 4x²

ii. The position of the term with negative exponent is changed from denominator to numerator or numerator to denominator depending on its initial position. If it is at the numerator, it is moved to the denominator. If otherwise it is at the denominator, it is moved to the numerator. When this is done, the negative exponent is changed to positive.

In our case, the first term has a negative exponent and it is at the numerator. We therefore move it to the denominator and change the negative exponent to  positive as follows;

\frac{1}{2x^3} . 4x^2

iii. We then solve the result as follows;

\frac{1}{2x^3} . 4x^2 = \frac{2}{x}

Therefore, 2x⁻³ . 4x² = \frac{2}{x}

b. 2x^4 • 4x^-3

i. Rewrite as follows;

2x⁴ . 4x⁻³

ii. The second term has a negative exponent, therefore swap its position and change the negative exponent to a positive one.

2x^4 . \frac{1}{4x^3}

iii. Now solve by cancelling out common terms in the numerator and denominator. So we have;

\frac{x}{2}

Therefore, 2x⁴ . 4x⁻³ = \frac{x}{2}

c. 2x^3y^-3 • 2x

i. Rewrite as follows;

2x³y⁻³ . 2x

ii. Change position of terms with negative exponents;

2x^3.\frac{1}{y^3} .2x

iii. Now solve;

\frac{4x^4}{y^3}

Therefore, 2x³y⁻³ . 2x = \frac{4x^4}{y^3}

8 0
3 years ago
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