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PolarNik [594]
3 years ago
9

What is the length of the transverse axis?

Mathematics
1 answer:
Basile [38]3 years ago
8 0

((x-2)÷6)-((y+1)÷8)=1.

(x÷6)-0.3333-(y+0.25)=1

i hope this helps

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What's -8.2 x 10 to the fifth power? Please explain your answer. Thank you!
Stolb23 [73]

First lets find -8.2 x 10 = -82 know we find 82^5 which is 82*82*82*82*82

-82*-82=6724 and then 6724*-82= -551368 and then -551368*-82 =45212176 and then 45212176*-82= -3707398432 and finally -3707398432 is our answer i checked the calc to after i did the hard math that took me forever i had some help from the calc and i got this hopefully this helps

8 0
3 years ago
Two buses leave towns 304 miles apart at the same time and travel toward each other. One bus travels 14 mih slower than the othe
8090 [49]

Answer:

The faster bus moves at 83mi/h and the slower one moves at 69mi/h.

Step-by-step explanation:

Let's define:

R₁ = rate of bus 1, this is the faster one.

R₂ = rate of bus 2, this is the slower one.

We know that one bus travels 14mi/h slower, then:

R₂ = R₁ - 14mi/h.

Now we know that:

Distance = Speed*Time.

If we add the distances that both busses travel in 2 hours, it should be equal to the initial distance between the buses, then:

R₁*2h + R₂*2h = 304 mi

Then we have the two equations:

R₂ = R₁ - 14mi/h

R₁*2h + R₂*2h = 304 mi

The first step is to replace the first equation in the second one, to get:

R₁*2h + (R₁ - 14mi/h)*2h = 304 mi

And now we can solve this for R₁.

R₁*2h + R₁*2h - 14mi/h*2h = 304 mi

R₁*4h - 28mi = 304mi

R₁*4h = 304mi + 28mi = 332mi

R₁ = 332mi/4h = 83mi/h

The faster bus moves at 83mi/h

And we know that the slower one moves at 14mi/h slower than this, then:

R₂ = R₁ - 14mi/h = 83mi/h - 14mi/h = 69 mi/h

7 0
2 years ago
What is the value of "h"?
kotegsom [21]

Answer:

h = 76

Step-by-step explanation:

2 + h - 48 = 30

h + 2 - 48 = 30

h - 46 = 30

h - 46 + 46 = 30 + 46

h = 76

4 0
2 years ago
Read 2 more answers
PLEASE HELP DUE TOMORROW 1. An artist is selling children’s crafts. Necklaces cost 2.25 each and bracelets cost 1.50 per each. a
Tems11 [23]

Answer:

Kindly check explanation

Step-by-step explanation:

Given that:

Cost per bracelet = 1.50

Cost per necklace = 2.25

Let :

number of necklace = n

Number of bracelet = b

Cost equation C ;

C = 1.5b + 2.25n

Number of necklace that could be sold for exactly $12

5 necklaces and 1 bracelet :

1.5 + 2.25(5) = 12.75

•2 necklaces and 5 bracelets:

1.5(5) + 2.25(2) = 12

• 3 necklaces and 3 bracelets

1.5(3) + 2.25(3) = 11.25

• 4 necklaces and 2 bracelets

1.5(2) + 2.25(4) = 12

• 3 necklaces and 5 bracelets

1.5(5) + 2.25(3) = 14.25

• 6 necklaces and no bracelets •

1.5(0) + 2.25(6) = 13.5

No necklaces and 8 bracelets

1.5(8) + 2.25(0) = 12

Amount charged per Tshirt = c

Setup fee = $40

Number of students in drama club = 21

Total cost of order = $187

Calculate C ;

Total order cost = set up fee + (cost per shirt * number of shirts)

Total order cost = 40 + 21c

187 = 40 + 21c

187 - 40 = 21c

147 = 21c

c = 147 / 21

C = 7

Hence cost per shirt = $7

5 0
2 years ago
What is the algebraic expressions of 8-6k​
Komok [63]
Eight decreased by six times the number k

The difference of eight and the product of six and the number k

Eight minus six times k

Six multiplied to k is less than 8
4 0
2 years ago
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