Answer:
The number of liters of 50% antifreeze solution is 50 and the number of liters of 90% antifreeze solution is 150
Step-by-step explanation:
Let
x ----> number of liters of 50% antifreeze solution
y ----> number of liters of 90% antifreeze solution
we know that
50%=50/100=0.50
90%=90/100=0.90
80%=80/100=0.80
x+y=200
x=200-y ------> equation A
0.50x+0.90y=0.8(200) -----> equation B
substitute equation A in equation B and solve for y
0.50(200-y)+0.90y=160
100-0.50y+0.90y=160
0.40y=160-100
0.40y=60
y=150 liters
Find the value of x
x=200-y
x=200-150=50 liters
therefore
The number of liters of 50% antifreeze solution is 50
The number of liters of 90% antifreeze solution is 150
(3) 8
Step-by-step explanation:
Note that ∆ADE is similar to ∆ABC. As such, the ratios of their legs are equal. Also note that AD = AB + BD.
BC/AB = DE/AD
BC/10 = 12/(10 + 5) = 12/15 = 4/5
or
BC = 10(4/5) = 8
Answer:
DDKEFD
Step-by-step explanation:
Answer:
Step-by-step explanation:
a trinomial that cannot be factored has no real roots.
here is one:
After graphing this trinomial has no intersections points with the x-axis wich means it has no roots
