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3 years ago

Helppppp aceeee/expertttsss quickkkk

Mathematics

1 answer:

baherus [9]3 years ago

8 0

Point A would be the answer because...
The distance between A and C is point B, which doesn't land on -2
Point A lands on -2.
The distance between A and D would be points B and C, both don't land on -2.
The opposite of -2 would be positive 2 and thats point D.
I hope this helps love.

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Answer:

A curve is given by y=(x-a)√(x-b) for x≥b. The gradient of the curve at A is 1.

Solution:

We need to show that the gradient of the curve at A is 1

Here given that ,

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Also, according to question at point A (b+1,0)

So curve at point A will, put the value of x and y

$0=(b+1-a) \sqrt{(b+1-b)}$

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According to multiple rule of Differentiation,

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By putting value of point A and putting value of eq 2 we get

$y^{\prime}=\sqrt{(b+1-b)}+(b+1-a) \times \frac{1}{2} \sqrt{(b+1-b)}$

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3 years ago

Pls pls help Show work :)

Natasha2012 [34]

9514 1404 393

Answer:

31.243 units

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you of the relationships between sides and angles in a right triangle. Using the attached figure, it is convenient to find the length of BE as an intermediate step in the solution.

Sin = Opposite/Hypotenuse

sin(30°) = BE/100

BE = 100·sin(30°)

Then ...

Tan = Opposite/Adjacent

tan(58°) = BE/x

x = BE/tan(58°) = 100·sin(30°)/tan(58°)

x ≈ 31.243 . . . . units

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Comment on the figure

The intermediate problem in creating the figure was to locate point D. That was accomplished by locating point C on a line at an angle of 58° CCW from the horizontal, using point B as a center. Then D is the intersection of BC with the x-axis. BE is drawn perpendicular to the x-axis.

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