A bag contains eight green marbles and four blue marbles. what is the probability of drawing a green marble on the second draw?

1 answer:

3 0

<span>2/3 probability of drawing a green marble on the second draw. If the marbles are replaced after each draw, the probability will always be 2/3 of a green marble being drawn. But for this problem, going to assume that the marbles are not replaced after each draw. So we have 2 possible scenarios. 1. The first marble drawn is green This even happens with probability of 2/3 and leaves you with 7 green marbles and 4 blue marbles. So the probability of picking a green marble again is 7/11. 2. The first marble drawn is blue This event happens with probability of 1/3 and leaves you with 8 green marbles and 3 blue marbles. So the probability of picking a green marble this time is 8/11 The total probability of picking a green marble on the 2nd pick is the sum of the product of each probability. So 2/3 * 7/11 + 1/3 * 8/11 = 14/33 + 8/33 = 22/33 = 2/3</span>

You might be interested in

How do you solve X/14=-21

Ket [755]

You multiply -21 by 14 to find x, and that would be -21 x 14 = -294, and that is your answer.

8 0

3 years ago

Jose is going to invest in an account paying an interest rate of 6.1% compounded continuously. How much would Jose need to inves

VikaD [51]

Answer:

P≈ 87784.11

Step-by-step explanation:

i don't know, I saw the solution on Delta Math