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olya-2409 [2.1K]
3 years ago
6

A bag contains eight green marbles and four blue marbles. what is the probability of drawing a green marble on the second draw?

Mathematics
1 answer:
Stolb23 [73]3 years ago
3 0
<span>2/3 probability of drawing a green marble on the second draw. If the marbles are replaced after each draw, the probability will always be 2/3 of a green marble being drawn. But for this problem, going to assume that the marbles are not replaced after each draw. So we have 2 possible scenarios. 1. The first marble drawn is green This even happens with probability of 2/3 and leaves you with 7 green marbles and 4 blue marbles. So the probability of picking a green marble again is 7/11. 2. The first marble drawn is blue This event happens with probability of 1/3 and leaves you with 8 green marbles and 3 blue marbles. So the probability of picking a green marble this time is 8/11 The total probability of picking a green marble on the 2nd pick is the sum of the product of each probability. So 2/3 * 7/11 + 1/3 * 8/11 = 14/33 + 8/33 = 22/33 = 2/3</span>
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Answer:

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Step-by-step explanation:

Extracting the key information from the question:

*** A baker uses 13 1/2 cups of flour to make key lime bread

*** She uses 2 1/4 cups to make each loaf.

*** She sells 2/3 of the loaves of bread that she makes.

Now, since she uses 2 1/4 to make each loaf, we will convert this into improper fraction.

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She uses a total of 13 1/2 cups of flour to make all loaves.

To find the number of loaves she makes, we will divide the overall quantity of flour used by the quantity used to make a loaf

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Since 13 1/2 and 2 1/4 are the same as 27/2 and 9/4 respectively (mixed to improper fractions), we will then divide 27/2 by 9/4

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Again, we learnt she sells 2/3 of the total loaves she makes.

Since total = 6, then 2/3 of 6 is:

2/3 × 6 = 4 loaves .

Therefore, the baker sells 4 loaves of key lime bread.

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