Question

What is the product? 3k/k+1*k^2-1/3k^3

Answer 1

Answer:

Product of the expression is $=\frac{k-1}{k^{2}}$

Step-by-step explanation:

We have to simplify the expression given as

$\frac{3k}{k+1}\times \frac{k^{2}-1}{3k^{3}}$

Now we will solve it

$\frac{3k}{k+1}\times \frac{k^{2}-1}{3k^{3}}$

$=\frac{3k}{k+1}\times \frac{(k+1)(k-1)}{3k^{3}}$

$=\frac{k-1}{k^{2}}$

So the simplified form is $=\frac{k-1}{k^{2}}$

Answer 2

We have [(3k)x(k-1)x(k+1)]/[3k^3x(k+1)] = (k-1)/k^2;