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3 years ago

HELP ME IM GONNA LOSE MY MIND IN MINUTES

Mathematics

2 answers:

VLD [36.1K]3 years ago

7 0

Oh gosh that’s hard try using a calculator if you can

Nonamiya [84]3 years ago

5 0

Answer:

I already lost my mind use a calculator that all I got for you sorry

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A group of 10 fisherman enjoy certain types of fish, 3 of them like salmon, 5 like trout and 2 like bass. A single fisherman is

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The histogram shows the number of items that customers bought during a trip to the grocery store one day. Four hundred customers

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Number of people who bought fewer than 30 items is (0.14 + 0.12 + 0.24)400 = 0.51 x 400 = 204

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3 years ago

a nationwide study of american homeowners revealed that 65% own at least one lawn mower. a lawn equipment manufacturer, locate

svetoff [14.1K]

Answer:

$z=\frac{0.6841 -0.65}{\sqrt{\frac{0.65(1-0.65)}{497}}}=1.5938$

We have a right tailed test then the p value would be:

$p_v =P(z>1.5938)=0.0555$

Step-by-step explanation:

Information provided

n=497 represent the random sample of homes selected

X=340 represent the number of homes with one or more lawn

$\hat p=\frac{340}{497}=0.6841$ estimated proportion of homes with one or more lawn

$p_o=0.65$ is the value that we want to test

z would represent the statistic

$p_v$ represent the p value (variable of interest)

System of hypothesis

We want to check if proportion of homeowners owning lawn mowers in charlotte is higher than 65%m so then the correct hypothesis are .:

Null hypothesis: $p\leq 0.65$

Alternative hypothesis: $p > 0.65$

The statistic is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the info given we got:

$z=\frac{0.6841 -0.65}{\sqrt{\frac{0.65(1-0.65)}{497}}}=1.5938$

We have a right tailed test then the p value would be:

$p_v =P(z>1.5938)=0.0555$

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3 years ago

Which expression is equivalent to 4x - (3x2 + x) + 5 - (2x2 + 1)?

creativ13 [48]

4x - (3x^2 + x) + 5 - (2x^2 + 1)

4x + x - 3x^2 - 2x^2 + 5 + 1

= 5x - 1x^2 + 6

Therefore the equivalent is 5x - 1x^2 + 6

6 0

3 years ago