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Likurg_2 [28]
3 years ago
10

student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te

sted will get version A of the test? Express your answer as a percent, and round to the nearest tenth
Mathematics
1 answer:
alexdok [17]3 years ago
4 0

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = \frac{1}{4}.

Thus, the probability that the student does not receive version A = 1-\frac{1}{4} = \frac{3}{4}.

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}+\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}+\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}

= (\frac{1}{4})^3\times (\frac{3}{4})^2+(\frac{1}{4})^4\times (\frac{3}{4})+(\frac{1}{4})^5

= (\frac{1}{4})^3\times (\frac{3}{4})[\frac{3}{4}+\frac{1}{4}+(\frac{1}{4})^2]

= (\frac{3}{4^4})[1+\frac{1}{16}]

= (\frac{3}{256})[\frac{17}{16}]

= 0.01171875 × 1.0625

= 0.01245

Thus, the probability that at least 3 out of 5 students receive version A is 0.0124

So, in percent the probability is 0.0124 × 100 = 1.24%

To the nearest tenth, the required probability is 1.2%.

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Identify two values that have a value less than 3 what is the answer to this question?
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Answer:

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Step-by-step explanation:

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10^-2 is a exponential that makes a number go down so 3.2 going down is less than 3

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3 years ago
Read 2 more answers
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Answer:

invested in ABC = $3200

Step-by-step explanation:

given data

total invest = $10,100

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dividends = $1.40 per share

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solution

we can say total money invest express as

total money invested = 32 × P + 23 × Q

here person buys stocks of ABC is P and buys stocks of stocks of XYZ is Q

$10,100 = 32 × P + 23 × Q  

we can also write this as by multiply 3 both side

$30,300 = 96 × P + 69 × Q  ......................1

and total dividends will be

total dividends =  1.2 × P +1.4 × Q

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we can also write this as by multiply 80 both side

$43200 = 96 × P + 112 × Q  ....................2

so from equation 1 and 2 , subtracting 1 from 2

we get

Q = 300

and P = 100

so that we invest 100 × 32

invested in ABC = $3200

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The answer for the expression is C.
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ra1l [238]

Answer:

P={3,4,5,6}

Step-by-step explanation:

Cube=6 sides={1,2,3,4,5,6}

P>2

P={3,4,5,6}

7 0
3 years ago
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