All categories

3 years ago

Two dice: Find the probability of rolling an odd number on the first die and an even number on the second die.

Mathematics

2 answers:

valkas [14]3 years ago

7 0

Both events happen with probability 1/2: there are 3 even numbers and 3 odd numbers in a die.

Since the two events are also independent (the outcome of the first die doesn't affect the outcome of the second), we have to multiply those probability.

So, you roll an odd number on the first die and an even number on the second die with probability

$\dfrac{1}{2}\cdot\dfrac{1}{2}=\dfrac{1}{4}$

klasskru [66]3 years ago

3 0

Answer:

1/4; 25%

Step-by-step explanation:

You might be interested in

Help I'm stuck on this question please help!

elena55 [62]

Answer:

A=20 degrees

Step-by-step explanation:

All of the interior angles of a triangle must add up to 180 degrees, so:

2x+5x+11x=180

18x=180

x=10

A=2(10)=20

Hope this helps!

7 0

3 years ago

Read 2 more answers

3/4 divided by 7 is ___

expeople1 [14]

Answer:

the answer is 3/28

Step-by-step explanation:

6 0

3 years ago

How can -6.75 + (10.25) be expressed as the sum of its integer and decimal parts

ArbitrLikvidat [17]

Answer:

-6.75 + (10.25) = ( (-6) + (10)) + ( (-0.75) + (0.25))

Here, the integer part = ( (-6) + (10))

Decimal part = ( (-0.75) + (0.25))

Step-by-step explanation:

Here, the given expression is: -6.75 + (10.25)

Now, -6.75 = (-6) + (-0.75)

Also, (10.25) = (10) + (0.25)

So, the expression can be written as

-6.75 + (10.25) = (-6) + (-0.75) + (10) + (0.25)

= ( (-6) + (10)) + ( (-0.75) + (0.25))

or, -6.75 + (10.25) = ( (-6) + (10)) + ( (-0.75) + (0.25))

Where the integer part is ( (-6) + (10))

and the decimal part is ( (-0.75) + (0.25))

3 0

3 years ago

23 cm

Alenkasestr [34]

Answer:

445.2 square cm

Step-by-step explanation:

The surface area consists of area of two bases and area of three leteral faces. Each lateral face is a rectangle with length of 23 cm and width of 6 cm.

The area of rectangle is

$A_{rectangle}=\text{length}\times\text{width}$