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Jobisdone [24]
4 years ago
7

Did do this right using PEMDAS 8/2(2+2) Solve: 8/2(4) 8/2*4 8/8 =1

Mathematics
2 answers:
Arte-miy333 [17]4 years ago
8 0

Answer:

nope its not. You should  count it like this  (8 / 2) * (2 + 2)

Step-by-step explanation:

(8 / 2) * (2 + 2)

4 * 4

16

DENIUS [597]4 years ago
5 0

\text{Hey there!}

\text{PEMDAS means: Parentheses, Exponents, Multiplication, Division, Addition}\\\text{, \& Subtraction}

\text{\underline{No}, it is \underline{NOT} correct because you had to work with the parentheses first}

\dfrac{8}{2}(2 + 2) = \ ? \\ \\ (2 + 2) = 4 \\ \\ \dfrac{8}{2}(4) = \ ? \\ \\ \dfrac{8}{2}= 4 \\ \\ \text{4(4)\ = 16} \\ \\ \boxed{\boxed{\huge\text{Answer should be: 16 }}}

\text{You had to do what was inside the parentheses first, then}\text{ divsion}

\text{Good luck on your assignment and enjoy your day!}

~\frak{LoveYourselfFirst:)}

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What is the factored form of the function f(x)=x^3+8x^2+5x−50?
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Answer:

the factors of  f(x)=x^3+8x^2+5x-50 are (x-2)(x+5)(x+5)

Step-by-step explanation:

We need to factorise the function f(x)=x^3+8x^2+5x-50

If a number is a factor of this function than it must be completely divisible by last co-efficient. Our last co-efficient is -50

Checking few numbers:

f(1)=(1)^{3}+8(1)^2+5(1)-50\\f(1)=1+8+5-50\\f(1)=-32\\Now \ putting \ x= 2 \\f(2)=(2)^{3}+8(2)^2+5(2)-50\\f(2)=8+8(4)+10-50\\f(2)=8+32+10-50\\f(2)=0

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The long division is shown in figure attached.

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