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3 years ago

10

If you take 3 by 2 what do you get

1 answer:

jekas [21]3 years ago

4 0

By multiplying the factors together you’ll get 6

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The cost of three pounds of grapes is $6.57 what is the constant proportionality that relates the cost in dollars to the number

NemiM [27]

$6.57/3 = $2.19 That is the answer.

7 0

3 years ago

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Evaluate 1/4 c + 3d when c = 6 and d = 7

Naddika [18.5K]

$\rule{50}{1}\large\blue\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}$

<em>Evaluate 1/4c+3d when c=6, and d=7.</em>

<em />

<em> </em> $\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}$

Replace c with 6, and d with 7:-

$\Large\text{$\displaystyle\frac{1}{4} (6)+3(7)$}$

$\bigstar$ On simplification,

$\Large\text{$\displaystyle\frac{1}{4} \times\frac{6}{1}+21$}$

$\bigstar$ On further simplification,

$\Large\text{$\displaystyle\frac{6}{4} +21$}$

$\bigstar$ On further simplification,

$\Large\text{$\displaystyle\frac{6}{4}+\frac{84}{4}$}$

$\bigstar$ Adding the numerators,

$\Large\text{$\displaystyle\frac{90}{4}$}$

$\bigstar$ Finally, Reducing the fraction:-

$\Large\text{$\displaystyle\frac{45}{2}$}$

$\Uparrow$ $\mathbb{OUR\:SIMPLIFIED\:EXPRESSION}$

<h3>Good luck with your studies.</h3>

$\rule{50}{1}\smile\smile\smile\smile\smile\smile\rule{50}{1}$

8 0

2 years ago

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What is the range of the equation

a_sh-v [17]

The range of the equation is $y>2$

Explanation:

The given equation is $y=2(4)^{x+3}+2$

We need to determine the range of the equation.

<u>Range:</u>

The range of the function is the set of all dependent y - values for which the function is well defined.

Let us simplify the equation.

Thus, we have;

$y=2 \cdot 4^{x+3}+2$

This can be written as $y=2^{1+2(x+3)}+2$

Now, we shall determine the range.

Let us interchange the variables x and y.

Thus, we have;

$x=2^{1+2(y+3)}+2$

Solving for y, we get;

$x-2=2^{1+2(y+3)}$

Applying the log rule, if f(x) = g(x) then $\ln (f(x))=\ln (g(x))$ , then, we get;

$\ln \left(2^{1+2(y+3)}\right)=\ln (x-2)$

Simplifying, we get;

$(1+2(y+3)) \ln (2)=\ln (x-2)$

Dividing both sides by $\ln (2)$ , we have;

$2 y+7=\frac{\ln (x-2)}{\ln (2)}$

Subtracting 7 from both sides of the equation, we have;

$2 y=\frac{\ln (x-2)}{\ln (2)}-7$

Dividing both sides by 2, we get;

$y=\frac{\ln (x-2)-7 \ln (2)}{2 \ln (2)}$

Let us find the positive values for logs.

Thus, we have,;

$x-2>0$

$x>2$

The function domain is $x>2$

By combining the intervals, the range becomes $y>2$

Hence, the range of the equation is $y>2$

7 0

3 years ago

The relationship represented by the table below is proportional ?

Natasha2012 [34]

Answer:

false

Step-by-step explanation:

Because it multiplying by 2's but 13x2=26 but it says 24 so that why it is false

8 0

3 years ago

Read 2 more answers

Alexxandr [17]

1. (2x + 3)(x + 1)
2. Prime
3. (4x - 1)(2x + 3)
4. Prime
5. (2x - 7)(x + 4)

7 0

2 years ago

Read 2 more answers