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3 years ago

You are supposed to distribute to only one term (the first).

Mathematics

2 answers:

Tom [10]3 years ago

6 0

Answer:

true

Step-by-step explanation:

There is no distribution (unless you count substitution) in the second set of terms.

Edit: I think I get what your question is now. You are supposed to distribute to every term inside the parenthesis (false)

algol [13]3 years ago

4 0

True, follow PEMDAS

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What is the distance between P(-3,-25) and Q(50,-2)

Karolina [17]

$Dist = (x2-x1)^{2} + (y2-y1)^{2}$

above is the distance formula, plugging your numbers from P(x1,y1) and Q(x2,y2).

$Dist = \sqrt{(50-(-3))^{2} + (-2-(-25))^{2} }$
or $\sqrt{ 53^{2} + 23 ^{2} }$

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3 years ago

4 week it drop 3 feet what is the unit rate

grin007 [14]

<span>In 4 weeks, it dropped 3 feet in total.
The unit rate of this is 3 feet / 4 weeks
If we simplify this into days, this will be the solutions
=> 4 weeks has (4 * 7) 28 days in total, so we need to divide 3 feet by 28 days to get the simplified unit rate.
=> 3 feet / 28 days
=> .107 feet / day.
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4 years ago

Find the solution set of 5x<36 when x ∈ n

Margaret [11]

Answer:

5x<36

5x/5 < 36/5

x < 7.2

4 0

3 years ago

Read 2 more answers

The ratio of the number of boys to the number of girls in a school is 5:7.If there are 600 students in the school,how many girls

nekit [7.7K]

So,

The secret to solving problems with ratios is to find the value of one unit.

5:7 = 12 units total

To find one unit, divide the total number of students by the total number of units.
600/12 = a

Simplify
50/1 = a
50 = a

The value of each unit is 50.

Now, multiply the units by the numbers in the ratio.
50(5) = b
250 = boys

50(7) = x
350 = x

There are 350 girls.

3 0

3 years ago

Read 2 more answers

Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

Andre45 [30]

Answer:

Option d) 5 to the power of negative 5 over 6 is correct.

$\dfrac{\sqrt[3]{\bf 5} \times \sqrt{\bf 5}}{\sqrt[3]{\bf 5^{\bf 5}}}= 5^{\frac{\bf -5}{\bf 6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

ie, $5^\frac{\bf -5}{\bf 6}$

Step-by-step explanation:

Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

It can be written as below

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}} \times 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{5^5}= 5^{\frac{-5}{6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

7 0

4 years ago