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inessss [21]
4 years ago
7

A block of mass M slides down an inclined plane that makes an angle θ with the horizontal. The coefficient of kinetic friction b

etween the block and the incline is μk. What is the magnitude of the normal force exerted by the incline on the block?
Physics
1 answer:
Llana [10]4 years ago
5 0

Answer:

Mg Cosθ

Explanation:

mass of block = M

Angle of inclination = θ

coefficient of friction = μk

The force of gravity acts of the block is Mg

there are two components of the weight

the component parallel to the inclined plane is Mg Sinθ

the component perpendicular to the plane of inclined is Mg Cosθ

So, the normal force exerted by the inclined is Mg Cosθ

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Explanation:

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An ice-skater is moving at a constant velocity across an icy pond, The skater throws a snowball directly ahead.
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Answer:

(D) It is equal to the original velocity of the skater.

Explanation:

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4 years ago
One gram of pure gold would contain lots of gold
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3 years ago
A cable passes over a pulley. Because the cable grips the pulley and the pulley has nonzero mass, the tension in the cable is no
topjm [15]

Answer:

\alpha=214.8 rad/s^2

Explanation:

We are given that

F_1=137 N

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Radius,r=0.723 m

We have to find the magnitude of its angular acceleration.

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Substitute the values

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