Answer: a) 112.88 * 10^3 N/C; b) The electric field point outward from the center of the sphere.
Explanation: In order to solve this problem we have to use the gaussian law so we use a gaussian surface at r=0.965 m and the electric flux is equal to Q inside/εo
E* 4*π*r^2= Q inside/εo
E= k*Q inside/r^2= 9*10^9*(6.53+5.15)μC/(0.965)^2=122.88 * 10 ^3 N/C
(3) 8.3 N/kg. The gravitational field strength at a point is the force per unit mass exerted on a mass placed at that point. So at the point where the Hubble telescope is, it is (9.1 x 10^4)N/(1.1 x 10^4 kg) = 8.3 N/kg
Fam
Pretty fast. Everything looks fast when running past a light pole
Answer:
The the specific volume and weight are 79.16m³/k mol and 49 N.
Explanation:
Given that,
Diameter = 3 m
Mass of N₂ = 5 kg
We need to calculate the volume of balloon
Using formula of volume




We need to calculate the specific volume in the balloon



Now, Molar mass of N₂ gas is 0.028 kg/mol
Now, Specific volume of N₂ gas in the balloon is


(b). We need to calculate the weight of the gas in the balloon
Weight of the balloon is dependent on the mass of the gas.
The weight of the gas is given by



Hence, The the specific volume and weight are 79.16m³/k mol and 49 N.