Question

If a 12 kg object's velocity changes from 5 m/s to 10 m/s in 5 s, what amount of force was applied to increase the speed of the object?

Answer 1

Answer:

12 N

Explanation:

Given that a 12 kg object's velocity changes from 5 m/s to 10 m/s in 5 s, what amount of force was applied to increase the speed of the object?

Solution

M = 12 kg

T = 5 s

The formula to use will be

F = ma

Where

Acceleration a = change in velocity/ time

Acceleration a = ( 10 - 5 ) / 5

Acceleration a = 5 / 5

Acceleration a = 1 m/s^2

Substitutes a into the formula above

F = ma

F = 12 × 1

F = 12 N

Therefore, the amount of force applied to increase the speed of the object is 12 N.