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kkurt [141]
3 years ago
9

How do you solve 9| x+8 | + 10 < 55 & how is it graphed

Mathematics
1 answer:
mafiozo [28]3 years ago
3 0
Hello!

First, let's write the problem.
9\left|x+8\right|+10\ \textless \ 55|x+8|+10\ \textless \ 55
Subtract 10 from both sides.
9\left|x+8\right|+10-10\ \textless \ 55-10
9\left|x+8\right|\ \textless \ 45
Divide both sides by 9.
\frac{9\left|x+8\right|}{9}\ \textless \ \frac{45}{9}
\left|x+8\right|\ \textless \ 5
When we got absolute value, we are going to get two results.
x+8\ \textless \ 5
and
x+8\ \textgreater \ -5

Let's solve the first one,
x+8\ \textless \ 5x+8\ \textless \ 5
Subtract 8 from both sides.
x+8-8\ \textless \ 5-8
x\ \textless \ -3x\ \textless \ -3

Let's solve the second one.
x+8\ \textgreater \ -5
Subtract 8 from both sides.
x+8-8\ \textgreater \ -5-8
x\ \textgreater \ -13x\ \textgreater \ -13

Let's combine the ranges.
-13\ \textless \ x\ \textless \ -3

The attachment shows how would you graph it.
You can feel free to let me know if you have any questions regarding this.
Thanks!

- TetraFish

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