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4 years ago

PLEASE HELP THIS IS PART OF A TEST!!!

SAT

2 answers:

kenny6666 [7]4 years ago

8 0

It would probably be a and c

torisob [31]4 years ago

4 0

I would say it's A and C, because it's good to use key words, but you always wanna keep your search general, with key words, hope this helped :)

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Approximately 10% of all people are left-handed. Consider a group of fifteen people.

Svetradugi [14.3K]

M. E. R. P.

I need to do this so sorry

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2 years ago

The word from the passage that best defines the topic is "youth. " "song. " "kiss. " "love. ".

Alona [7]

There are different kinds of poem. The word from the passage that best defines the topic is love.

<h3>An Ode on a Grecian Urn?</h3>

This is known as a poem that was written by John Keats in 1820. The “Ode on a Grecian Urn” sees to evaluate the close linkage or the relationship that exist between art, beauty, and truth.

The speaker in the poem stated that the beauty that humankind is very close to the truth. The word of the below text that summarized it is Love. This is because this aspect of the poem is talking more about love.

See full question below

Read the passage from "Ode on a Grecian Urn."

Fair youth, beneath the trees, thou canst not leave

Thy song, nor ever can those trees be bare;

Bold Lover, never, never canst thou kiss,

Though winning near the goal—yet, do not grieve;

She cannot fade, though thou hast not thy bliss,

For ever wilt thou love, and she be fair!

The word from the passage that best defines the topic is

"youth."

"song."

"kiss."

"love."

Learn more about love from

brainly.com/question/931164

7 0

2 years ago

All the following are advantages of being a prep cook EXCEPT

Salsk061 [2.6K]

Answer:

the ability to work less than a line cook while making more money.

Hope this helps!

Sincerely; Victoria<3

Explanation:

7 0

3 years ago

During a rainfall, the depth of water in a rain gauge increases at a rate modeled by r(t)=0.5+tcos(πt380) r ( t ) = 0.5 + t cos

Tresset [83]

The function r(t)= 0.5 + t cos(πt³/80) is an illustration of a cosine function

The depth of water in the rain gauge increases by 1.466cm from t = 0 to t = 3

<h3>How to determine the increase in water depth?</h3>

The function is given as:

r(t)= 0.5 + t cos(πt³/80)

When t = 0, the depth of water is:

r(0)= 0.5 + 0 * cos(π *0³/80)

Evaluate

r(0) = 0.5

When t = 3, the depth of water is:

r(3)= 0.5 + 3 * cos(π *3³/80)

Evaluate

r(3)= 1.966

Calculate the difference (d) in the depths

d = r(3) - r(0)

So, we have:

d = 1.966 - 0.5

Evaluate

d = 1.466

Hence, the depth of water in the rain gauge increases by 1.466cm from t = 0 to t = 3

Read more about cosine functions at:

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4 0

3 years ago

wariber [46]

<h2>Right answer: I and II only </h2>

If we already have the formula to find how temperature measured in degrees Fahrenheit, relates to a temperature in degres Celsius:

$C=(F-32)\frac{5}{9}$ (1)

We can know the formula to find how temperature measured in degrees Celsius, relates to a temperature in degres Fahrenheit, only by isolating F:

$F=(\frac{9}{5}C)+32$ (2)

Having both formulas, let’s begin:

I) If we want to prove that a temperature increase of 1 degree Fahrenheit is equivalent to a temperature increase of 5/9 degree Celsius:

Beginning with $1\ºF$ :

$C=(1\ºF-32)\frac{5}{9}=-17.22\ºC$

This means: $1\ºF=-17.22\ºC$

Now we are going to increase 1 degree Farenheit. In other words, we are going to use $2\ºF$ :

$C=(2\ºF-32)\frac{5}{9}=-16.66\ºC$

This means: $2\ºF=-16.66\ºC$

Calculating the difference between $-16.66\ºC$ and $-17.22\ºC$ :

$-16.66\ºC-(-17.22\ºC)=0,55\ºC$ >>>>This is equal to 5/9 degree Celsius, hence is correct

II) If we want to prove that a temperature increase of 1 degree Celsius is equivalent to a temperature increase of 1.8 degrees Fahrenheit:

Beginning with $1\ºC$ :

$F=(\frac{9}{5}1\ºC)+32$

$F=33.8\ºF$

This means: $1\ºC=33.8\ºF$

Now we are going to increase 1 degree Celsius. In other words, we are going to use $2\ºC$ :

$F=(\frac{9}{5}2\ºC)+32$

$F=35.67\ºF$

This means: $2\ºC=35.67\ºF$

Calculating the difference between $35.67\ºF$ and $33.8\ºF$ :

$35.67\ºF-33.8\ºF=1.8\ºF$ >>>>This is a proof of the statement, hence is also correct.

<h2 />

III) If we want to prove that a temperature increase of 5/9 degree Fahrenheit is equivalent to a temperature increase of 1 degree Celsius:

Beginning with $1\ºC$ :

$F=(\frac{9}{5}1\ºC)+32$

$F=33.8\ºF$

This means: $1\ºC=33.8\ºF$

Now we are going to add $\frac{5}{9}\ºF$ :

$33.8\ºF+\frac{5}{9}\ºF=34.35\ºF$

And use this value in the Celsius formula:

$C=(34.35\ºF-32)\frac{5}{9}=1.30\ºC$

This means: $1.30\ºC=34.35\ºF$

In other words: An increase in 5/9 degree Fahrenheit is equivalent to a temperature increase of 1.30 degree Celsius, <u>not 1 degree Celsius</u>.

Therefore this statement is incorrect.

4 0

3 years ago