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In-s [12.5K]
3 years ago
10

What is 350/100 as a decimal and percent

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
7 0
3.5
350%. Hope it helped
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(03.01 LC)<br><br> What is the length of leg y of the right triangle? (1 point)
EastWind [94]

Answer:

<h2>A</h2>

Step-by-step explanation:

The complete question is

What is the length of leg y of the right triangle?

A right triangle with hypotenuse 26 and legs 24 and y

  • 10
  • 14
  • 24
  • 26

We need to use the Pythagorean Theorem, where h=26 and x=24,

h^{2} =x^{2} +y^{2}\\ 26^{2}=24^{2}+y^{2}\\y=\sqrt{26^{2}-24^{2}}\\ y=\sqrt{676-576}\\ y=\sqrt{100}\\ y=10

Therefore, the right answer is A. The length of the missing leg is 10 units.

4 0
3 years ago
A group of rectangular prisms is shown.
scoray [572]

Answer:

D, E and F

calculating the volume of regular bodies like prims works by multiplication alone.

you need some addition for surface area and for more complicated bodies that when the volume can't be calculated in one step

8 0
2 years ago
The graphs below have the same shape. What is the equation of the blue graph? A. g(x) = (x-4)2 - 2 B. g(x) = (x + 4)2 + 2 C. g(x
Doss [256]

Answer:

The answer is D. g(x) = (x+4)^2 - 2

Step-by-step explanation:

This is because f(x) = (x-h)^2 + k

where h = horizontal translations and k = vertical translations

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Its upside down but what are the answers to all of the equations?
elena-14-01-66 [18.8K]

Answer: here I just fliped it

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Read 2 more answers
Prove whether the following are identities 2tanh 1/2x / 1−tanh^2 1/2 x = sinh x​
Tanzania [10]

Recall that

\cosh^2(x) - \sinh^2(x) = 1

Dividing both sides by cosh²(x) gives

1 - \tanh^2(x) = \mathrm{sech}^2(x)

Also, recall the identity

\sinh(2x) = 2\sinh(x)\cosh(x)

Then

\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \dfrac{2\tanh\left(\frac x2\right)}{\mathrm{sech}^2\left(\frac x2\right)} \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\tanh\left(\dfrac x2\right)\cosh^2\left(\dfrac x2\right) \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\sinh\left(\dfrac x2\right)\cosh\left(\dfrac x2\right) \\\\\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \sinh(x)

4 0
3 years ago
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