Answer:
12.94%
Step-by-step explanation:
r = 100(1/2)^(d/5) = 100((1/2)^(1/5))^d ≈ 100(.87055)^d
The daily decrease is 1 - 0.87055 = 0.12944 ≈ 12.94%
Answer:
a. E(x) = 3.730
b. c = 3.8475
c. 0.4308
Step-by-step explanation:
a.
Given
0 x < 3
F(x) = (x-3)/1.13, 3 < x < 4.13
1 x > 4.13
Calculating E(x)
First, we'll calculate the pdf, f(x).
f(x) is the derivative of F(x)
So, if F(x) = (x-3)/1.13
f(x) = F'(x) = 1/1.13, 3 < x < 4.13
E(x) is the integral of xf(x)
xf(x) = x * 1/1.3 = x/1.3
Integrating x/1.3
E(x) = x²/(2*1.13)
E(x) = x²/2.26 , 3 < x < 4.13
E(x) = (4.13²-3²)/2.16
E(x) = 3.730046296296296
E(x) = 3.730 (approximated)
b.
What is the value c such that P(X < c) = 0.75
First, we'll solve F(c)
F(c) = P(x<c)
F(c) = (c-3)/1.13= 0.75
c - 3 = 1.13 * 0.75
c - 3 = 0.8475
c = 3 + 0.8475
c = 3.8475
c.
What is the probability that X falls within 0.28 minutes of its mean?
Here we'll solve for
P(3.73 - 0.28 < X < 3.73 + 0.28)
= F(3.73 + 0.28) - F(3.73 + 0.28)
= 2*0.28/1.3 = 0.430769
= 0.4308 -- Approximated
This questions can be answered with a calculator, but I have an impression it is meant to be a mental calculation problem, which can be solved as follows.
We know that 10*10=100, in otherwords, √ 100 = 10 which is greater than 9.4247.
We also know that √ 108 is greater than √ 100 =10
So we can conclude that
√ 108 > √ 100 = 10 > 9.4247
or simply
√ 108 > 9.4247
by the transitive property of logical propositions.
Answer:
Step-by-step explanation:
A box plot is the diagrammatic representation of the five number summary. It includes 5 items:
The minimum.
Q1 = the first quartile or the 25% mark.
The median.
Q3 = the third quartile or the 75% mark.
The maximum.
Rearranging the data in ascending order, it becomes
169, 163, 153, 166, 149, 148, 146, 145, 152, 163
145, 146, 148, 149, 152, 153, 163, 163, 166, 169
Minimum = 145
Maximum = 169
Median = (152 + 153)/2 = 152.5
The median divides the data into two equal halves. The middle of the lower halve is Q1 while the middle of the upper halve is Q3
Q1 = 148
Q3 = 163
The diagram of the box plot is shown in the attached photo
