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3 years ago

5

what is the circumference and area of a circle with a radius of 4 meters? round your answer to the nearest tenth.

1 answer:

sattari [20]3 years ago

4 0

C=2pir
a=pir^2

r=4
c=2pi4=8pi m
a=pir^2=pi4^2=16pi m^2

circumference=8pi meters
area=16pi square meters

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The first month a company was open, it had 2 employees. At the end of 6 months, the company had 10 employees. If the number of e

deff fn [24]

the equation would be 2[6]+10 however if we were to solve it would have been 2(6)+10 = 22 employees

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2 years ago

An ice cream cone is 5" deep and 2" in top diameter. One scoop of vanilla ice cream, 2" in diameter, is placed on the cone. If t

Ratling [72]

If the total volume of the ice cream exceeds the internal volume of the cone, then it will overflow.

Volume of icecream = 4/3 * pi * r^3 = 4/3*pi*(1)^3 = 4.189 cu. in.Volume of cone = 1/3 * pi * r^2 * h = 1/3*pi*(1)^2*5 = 5.236 cu. in.

Since Volume of cone > Volume of icecream, the cone will not overflow.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

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3 years ago

Help please lol soon

Yuliya22 [10]

Answer:

d.

D: {-7, 0, 2, 6}

R: {-13, 0, 5, 13}

Step-by-step explanation:

Domain of a relation is the set of all input values (x-values) while the range is the set of all corresponding output values (y-values) in a given relation.

Given the relation represented by the table above,

Domain would be: {-7, 0, 2, 6}

Range: {-13, 0, 5, 13}

5 0

3 years ago

How can I factor 5x^2 + 26x - 24 = 0 using the completing the square method.

kifflom [539]

<h2><u>QUADRATIC EQUATION</u></h2>

<h2> $\mathbb{ANSWER:}$ </h2>

$\bold{x = 0.8 \: } \: \sf \: {\color{grey}or} \: \: \: \bold{ x= \frac{4}{5} } \\$

$\bold{x = - 6}$

— — — — — — — — — —

<h3>Step-by-step explanation:</h3>

<u>How can </u><u>we</u><u> factor 5x^2 + 26x - 24 = 0 using the completing the square </u><u>method?</u>

Let's solve your equation step-by-step.

$\bold{Given \: Equation: \color{brown} 5x²+26x-24=0}$

First, add 24 to both sides.

$\bold{5x²+26x-24 - \purple{ 24} = 0 + \purple{24}}$

$\bold{ \implies \: 5x²+26x = 24 }$

Since the coefficient of 5x² is 5, divide both sides by 5.

$\bold{ \frac{5 {x}^{2} + 26x }{5} = \frac{24}{5} } \\$

$\bold{ \implies \: {x}^{2} + \frac{26}{5} x = \frac{24}{5} } \\$

The coefficient of 26/5x is 26/5. So, let b=26/5.

Then we need to add (b/2)²=169/25 to both sides to complete the square.

Add 169/25 to both sides.

$\bold{ {x}^{2} + \frac{26}{5} x + \frac{ \purple{169}}{ \purple{25}}= \frac{24}{5} + \frac{ \purple{169}}{ \purple{25}} } \\$

$\bold{ \implies \:\bold{ {x}^{2} + \frac{26}{5} x + \frac{ 169}{ {25}}= \frac{289}{25} } } \\$

Factor the left side.

$\bold{(x + \frac{13}{5} ) {}^{2} = \frac{289}{25} } \\$

Take square root.

$\bold{x + \frac{13}{5} = ± \: \sqrt{ \frac{289}{25} }} \\$

Then, add (-13)/5 to both sides.

$\bold{x + \frac{13}{5} + \frac{\purple{ - 13} }{\purple{ 5}} = \frac{{ - 13} }{{ 5}} ± \: \sqrt{ \frac{289}{25}}} \\$

$\bold{ \: x = \frac{ - 13}{5} ± \sqrt{ \frac{289}{25} } } \\$

$\implies \: \underline{ \boxed{ \bold{ \frac{4}{5} } \sf \: \: or \: \: \bold{ x = - 6}}} \\$

_______________❖_______________

3 0

2 years ago

Read 2 more answers

You are making a welding fixture and must cut down a length of copper tubbing from 15 1/8 inches to 8 3/4 inches. If the leftove

Bumek [7]

Answer: $6\dfrac{3}{8}\text{ inches}$

Step-by-step explanation:

Given: Original length = $15\dfrac{1}{8}$ inches

$=\dfrac{8\times15+1}{8}=\dfrac{121}{8}$ inches ( In improper fraction )

Length of piece cut from original = $8\dfrac{3}{4}$ inches

$=\dfrac{4\times8+3}{4}$ $= \dfrac{35}{4}$ inches ( In improper fraction )

Length of piece leftover piece = (Original length ) - (Length of piece cut )

$=\dfrac{121}{8}-\dfrac{35}{4}\\\\=\dfrac{121-2\times35}{8}\\\\=\dfrac{121-70}{8}\\\\=\dfrac{51}{8}\\\\=6\dfrac{3}{8}\text{ inches}$

Hence, the leftover piece will be $6\dfrac{3}{8}\text{ inches}$ long.

6 0

3 years ago