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Gelneren [198K]
3 years ago
5

Could someone help me with math please and please txt back

Mathematics
1 answer:
Pani-rosa [81]3 years ago
3 0
What do you need help on?

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How many decimeters are in 3.5 dekameters? Use the metric table to help answer the question.
Ivahew [28]

350 decimeters are there in 3.5 decameter

<em><u>Solution:</u></em>

We have to find the decimeters in 3.5 decameters

<em><u>Use the metric table:</u></em>

1 kilometre (km) = 10 Hectometres (hm) = 1000 m

1 Hectometre (hm) = 10 Decametres (dcm) = 100 m

1 Decametre (dcm) = 10 Metres (m)

1 Metre (m) = 10 Decimetres (dm) = 100 cm = 1000 mm

1 Decimetre (dm) = 10 Centimetres (cm)

1 decimeter = 0.1 meter

1 Centimetre (cm) = 10 Millimetres (mm)

1 centimeter = 0.01 meter

1 millimeter = 0.001 meter

From above metric table, we find that

100 decimeter = 1 decameter

Then, convert 3.5 decameter to decimeter

100 x 3.5 decimeter = 3.5 x 1 decameter

350 decimeter = 3.5 decameter

Thus 350 decimeters are there in 3.5 decameter

5 0
3 years ago
When does the proportion form of newton's second law take the form of an equation?
Brrunno [24]
Newton's law of motion has three parts. The second of which states that the force needed to move an object is directly proportional to the acceleration of the motion. The proportion can be written as,
              F = ka
where k is the constant of proportionality. This can be substituted with the mass of the object such that the equation would become. 
                F = ma
where F is force, m is mass, and a is acceleration. 
8 0
3 years ago
Find the slope of this graph. Screenshot given.
aleksklad [387]
It would be 4 I think
6 0
3 years ago
Read 2 more answers
Simplify 3x + 2y + y + 4x.
Anika [276]
Add like variables together

3x + 4x + 2y + y

7x + 3y

7x + 3y is your answer

hope this helps
6 0
3 years ago
Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by
a_sh-v [17]

Answer:

Dimension of the box is 16.1\times 7.1\times 2.45

The volume of the box is 280.05 in³.

Step-by-step explanation:          

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the box?

Solution :

Let h be the height of the box which is the side length of a corner square.

According to question,

A sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

The length of the box is L=21-2h

The width of the box is W=12-2h

The volume of the box is V=L\times W\times H

V=(21-2h)\times (12-2h)\times h

V=(21-2h)\times (12h-2h^2)

V=252h-42h^2-24h^2+4h^3

V=4h^3-66h^2+252h

To maximize the volume we find derivative of volume and put it to zero.

V'=12h^2-132h+252

0=12h^2-132h+252

Solving by quadratic formula,

h=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

h=\frac{-(-132)\pm\sqrt{132^2-4(12)(252)}}{2(12)}

h=\frac{132\pm72.99}{24}

h=2.45,8.54

Now, substitute the value of h in the volume,

V=4h^3-66h^2+252h

When, h=2.45

V=4(2.45)^3-66(2.45)^2+252(2.45)

V\approx 280.05

When, h=8.54

V=4(8.54)^3-66(8.54)^2+252(8.54)

V\approx -170.06

Rejecting the negative volume as it is not possible.

Therefore, The volume of the box is 280.05 in³.

The dimension of the box is

The height of the box is h=2.45

The length of the box is L=21-2(2.45)=16.1

The width of the box is W=12-2(2.45)=7.1

So, Dimension of the box is 16.1\times 7.1\times 2.45

6 0
4 years ago
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