Answer:
<h3>Area of a circle= πr²</h3><h2>50.24 = 3.14 *r²</h2><h2>r²= 50.24/3.14</h2><h2>r² =16</h2><h2>r= √16</h2><h2>r = 4</h2>
<span>3x2− 5x + 5 = 0.
a=3 b=-5 c=5
A. a = 3, b = 5, c = 5
B. a = 3, b = −5, c = 5
C. a = 5, b = −5, c = 0
D. a = −3, b = 5, c = −5
answer is B
</span>
We are given the function <span>f(x) = 3^x+1 - 2 and is asked for the asymptote and y-intercept. In this case, we transform the function to
y +2 = 1/3^(x+1)-1
y = 1-2</span>/3^(x+1)-1/(3^(x+1)-1)
let 3^(x+1)-1 = 0
<span>1/3^(x+1) = 0
x = infinity
when x = infinity
y = 0 - 2
y = -2
The y-intercept is the value where x = 0. substituting,
y = 3^(0+1) - 2 = 1 </span>
Answer: The answer is -24 if you start at 0 points
Step-by-step explanation:
3 x 8 = 24 if it starts at zero put a negative symbol (-) to 24.
1. x>-2 distribute the three and get 3x+6>0 subtract the 6 to get 3x>-6 then divide by 2 to get -2.
2.x>6 distribute 8 to get 8x+8 and distribute 7 to get 7x+14. Subtract over the 8 to get 8x>7x+6 then subtract over 7x to get x>6
3.distribute the 9 and the 4 to get 9x-27<4x+40 add over the 27 and get 9x<4x+67 subtract over the 4x to get 5x<67 divide by 5 and get x<67/5
4. distribute the 3 and the 2 to get 3x+3 + 2x+4>0 add together the like terms 3x+2x=5x and 3+4=7 to get 5x+7>0 subtract over the seven to get 5x>-7 and then divide by 5 to get x>-7/5 5. first add over -7 to get -9x/11<2. after that multiply by 11 to get -9x<22 then divide by -9 (MAKE SURE YOU FLIP THE INEQUALITY SIGN WHEN MULTIPLYING OR DIVIDING BY A NEGATIVE LIKE -9 IN THIS CASE) you get x>-22/9 6. Add over the 5 to get 3x<9 divide by 3 and get x<3
