Question

(3x+4)^2=14 what are the solutions?

Answer 1

$\bf (3x+4)^2=14\implies \sqrt{(3x+4)^2}=\pm\sqrt{14}\implies 3x+4=\pm\sqrt{14} \\\\\\ 3x=\pm \sqrt{14}-4\implies x=\cfrac{\pm \sqrt{14}-4}{3}\implies x= \begin{cases} \cfrac{\sqrt{14}-4}{3}\\\\ \cfrac{- \sqrt{14}-4}{3} \end{cases}$