3 years ago

(3x+4)^2=14 what are the solutions?

1 answer:

7 0

$\bf (3x+4)^2=14\implies \sqrt{(3x+4)^2}=\pm\sqrt{14}\implies 3x+4=\pm\sqrt{14}
\\\\\\
3x=\pm \sqrt{14}-4\implies x=\cfrac{\pm \sqrt{14}-4}{3}\implies x=
\begin{cases}
\cfrac{\sqrt{14}-4}{3}\\\\
\cfrac{- \sqrt{14}-4}{3}
\end{cases}$

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