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3 years ago

I NEED HELP

Mathematics

1 answer:

Nana76 [90]3 years ago

5 0

A. 125 is the answer to your question

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Which of the following fractions is not equivalent to 8/22 ?

xz_007 [3.2K]

B because 5xanything ends in 0 or 5

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3 years ago

Miss Sarah only wants one half of a sandwich she says Mr. tom will need one 16th of a pound of cheese for her sandwich Mr. Tom s

Maurinko [17]

Well the 1/8 is for the whole sandwich because it is double the cheese that Ms. Sarah said. So Ms. Sarah is correct because it is for half of the sandwich.

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3 years ago

Estimate to the nearest a) integer and b) tenth *<br> 15 over 2 integer

Sliva [168]

15/2 = 7.5 Im sorry don't know about the integer form

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3 years ago

PLZ HELP HURRY!!! HAVE A DEADLINE!!!

Lynna [10]

Answer:

y = -2x - 6

The y-intercept will be (0,-6)

One point will be at (1,-8)

The line will go downward since it is a negative slope

Step-by-step explanation:

y−2=−2(x+4)

Distribute

y - 2 = -2x - 8

Move the constant to the other side

y - 2 = -2x - 8

+2 = +2

y = -2x - 6

8 0

4 years ago

Triangle ABC was dilated with the origin as the center of dilation to create triangle A'B'C'. The triangle was dilated using a s

victus00 [196]

Answer:

$A'(-0.25,0.75)\\\\B'(1.75,-0.25)\\\\C'(-1,-0.25)$

Step-by-step explanation:

A Dilation is defined as a transformation in which the image and the pre-image have the same shape, but their sizes are different.

When the scale factor is greater than 1, the image obtained after the dilation is greater than the pre-image and it is an "Enlargement".

When the scale factor is is between 0 and 1, the image obtained after the dilation is smaller than the pre-image and it is an "Reduction".

In this case you know that the triangle ABC was dilated by this scale factor:

$scale\ factor=\frac{1}{4}$

With the origin as the center of dilation.

Since:

$0$

It is a Reduction.

You can identify that the vertices of the triangle ABC are:

$A(-1,3)\\\\B(7,-1)\\\\C(-4,-1)$

So you need to multiply the coordinates of each vertex of the triangle ABC by $\frac{1}{4}$ , in order to get the coordinates of the triangle A'B'C. Then, you get:

$A'=(\frac{1}{4}(-1),\frac{1}{4}(3))=(-0.25,0.75)\\\\B'(\frac{1}{4}(7),\frac{1}{4}(-1))=(1.75,-0.25)\\\\C'(\frac{1}{4}(-4),\frac{1}{4}(-1))=(-1,-0.25)$

5 0

3 years ago