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Serggg [28]
3 years ago
5

Can someone please help?

Mathematics
1 answer:
Shalnov [3]3 years ago
4 0

Answer:

c. 50

Step-by-step explanation:

count each full block and every block that is more than half full as 1 each, ignore every block that is less than half full.

I got exactly 50 using this method before looking at the available answers.

In multiple choice math problems try to ignore the possible answers until you have determined what you think it ought to be.  If the answer you found is in the list you have more confidence you are right, if the answer you got is not in the list you know you did something wrong... just a hint :)

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How many sales would you make a week? i would make between 3 and 5 sales per week?
svp [43]
You will make 4 sales if you are making a sale between 3 and five because 4 is whats in between 3 and 5. If your are to compute you will make a sale of average 4 because the average of 3 and 4 is 5. Computed as 3+5/2=4.
7 0
3 years ago
An arc on a circle measures 85°. The measure of the central angle, in radians, is within which range? 0 to StartFraction pi Over
barxatty [35]

Answer:

0 to StartFraction pi Over 2

Step-by-step explanation:

we know that

If the arc on a circle measures 85 degrees, then the measure of the central angle is also 85 degrees too

so

The central angle in degrees is within the range (0,90^o)

Convert to radians

Remember that

\frac{\pi}{2}\ radians=90^o

therefore

the range in radians is (0,\frac{\pi}{2})

0 to StartFraction pi Over 2

3 0
3 years ago
Read 2 more answers
Place these numbers on the number line. 1/4, 2/3, 3/4, 6/8
Lelu [443]
The best way to put them into a number line is to make sure that they've all got the same denominator, which in this case, will be 24, as this is the lowest common multiple of 3,4 and 8. You will then need to multiply these fractions accordingly. The first one (1/4) will need to be multiplied by 6 to get a denominator of 24, so this will then give you a result of 6/24. The second one (2/3), will need to be multiplied by 8, which will then give you a result of 16/24. The third one (3/4)will also need to be multiplied by 6, giving you 18/24. The final one (6/8) will need to be multiplied by 3, giving you 18/24. You will then need to put these in order, which will be- 1/4, 2/3, 3/4, and 6/8. The alternative method is to turn these into decimals- 1/4 is equivalent to 25%, which is equal to 0.25. 2/3 is equivalent to 66.66%, which is equivalent to 0.66. 3/4 is equivalent to 75%, which is equal to 0.75. 6/8 is also equivalent to 75%, which is equal to 0.75, you can then easily line them up this way. Hope this has been able to help you
4 0
3 years ago
Suppose that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another br
Lina20 [59]

Answer:

The differential equation for the amount of salt A(t) in the tank at a time  t > 0 is \frac{dA}{dt}=12 - \frac{2A(t)}{500+t}.

Step-by-step explanation:

We are given that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another brine solution is pumped into the tank at a rate of 3 gal/min, and when the solution is well stirred, it is then pumped out at a slower rate of 2 gal/min.

The concentration of the solution entering is 4 lb/gal.

Firstly, as we know that the rate of change in the amount of salt with respect to time is given by;

\frac{dA}{dt}= \text{R}_i_n - \text{R}_o_u_t

where, \text{R}_i_n = concentration of salt in the inflow \times input rate of brine solution

and \text{R}_o_u_t = concentration of salt in the outflow \times outflow rate of brine solution

So, \text{R}_i_n = 4 lb/gal \times 3 gal/min = 12 lb/gal

Now, the rate of accumulation = Rate of input of solution - Rate of output of solution

                                                = 3 gal/min - 2 gal/min

                                                = 1 gal/min.

It is stated that a large mixing tank initially holds 500 gallons of water, so after t minutes it will hold (500 + t) gallons in the tank.

So, \text{R}_o_u_t = concentration of salt in the outflow \times outflow rate of brine solution

             = \frac{A(t)}{500+t} \text{ lb/gal } \times 2 \text{ gal/min} = \frac{2A(t)}{500+t} \text{ lb/min }

Now, the differential equation for the amount of salt A(t) in the tank at a time  t > 0 is given by;

= \frac{dA}{dt}=12\text{ lb/min } - \frac{2A(t)}{500+t} \text{ lb/min }

or \frac{dA}{dt}=12 - \frac{2A(t)}{500+t}.

4 0
3 years ago
Does anyone know??????
masha68 [24]

Answer:

y=23x+4

Step-by-step explanation:

3 0
3 years ago
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