Given:
The equations are
To find:
Which function is changing more quickly.
Solution:
The slope intercept form of a line is
Where m is slope and b is y-intercept.
On comparing with the slope intercept form, we get
On comparing with the slope intercept form, we get
Since, 
, it means the absolute rate of change of second function is greater than the first function.
Therefore, the second function is changing more quickly.
The circumference of a circle is given by: 2πr, where r is the radius of the circle. Equating 4π, we have 2πr = 4π so the radius of the circle is: r = 4/2 = 2. Then, the area of the circle is given by πr ^ 2 = π * (2 ^ 2) = 4π.Since the square and the circle have the same area, then: Let L be the side of the square, we have: L ^ 2 = 4π, clearing L = 2 * (π ^ (1/2))The perimeter of a square is the sum of its sides: P = L + L + L + L = 2 * (π ^ (1/2)) + 2 * (π ^ (1/2)) + 2 * (π ^ (1/2)) + 2 * (π) ^ (1/2)) P = 8 * (π ^ (1/2))
Answer:
20(4 + 5)
Step-by-step explanation:
GCF is just the biggest number each value can be divided by. Here, it's 20, so that goes outside of the parenthesis. Now, what can you multiply by 20 to get 80? 4, so that goes in the second box. What can you multiply by 20 to get 100? 5, so that goes in the last box. You can check your answer by doing 80 + 100 = 180; 20(9) = 180.
Answer:
Student 2 and Student 3
Step-by-step explanation:
Student 2
-(5r - 3s + 1)
= - 5r +3s - 1
Student 3
= - 5r +3s - 1
Based in the given figure, we are being asked to solve the area and the perimeter of the semicircle. As we evaluate the problem, we can get a radius measurement from the rectangle. Hence, the radius is half of 4 inches which is 2 inches and since we know the formula for solving the area of a circle which is Area = pi*r², dividing the result by two, we able to get the area of the half of a circle which is equivalent to the area of the semicircle.
Area of circle = pi*r²
Area of circle = 3.14*(2)² = 12.56
Therefore, area of semicircle is = (1/2) 12.56
Area of semicircle = 6.28 inches²
Solving for the perimeter:
Semicircle Perimeter = 1/2 * pi* d+d where d is the diameter (diameter = 4 inches)
Semicircle Perimeter = 1/2 * 3.14*4+4
Semicircle Perimeter = 10.28 inches
