Answer:
C.I = 0.7608 ≤ p ≤ 0.8392
Step-by-step explanation:
Given that:
Let consider a random sample n = 400 candidates where 320 residents indicated that they voted for Obama
probability 
= 0.8
Level of significance ∝ = 100 -95%
= 5%
= 0.05
The objective is to develop a 95% confidence interval estimate for the proportion of all Boston residents who voted for Obama.
The confidence internal can be computed as:

where;
=
= 1.960
SO;






= 0.8 - 0.0392 OR 0.8 + 0.0392
= 0.7608 OR 0.8392
Thus; C.I = 0.7608 ≤ p ≤ 0.8392
It is a simple problem where 120 centimeters need to be increased by 24%. The increased length can be found by:
120 * (24/100)
= 12 * (24/10)
= 288/10
= 28.8 centimeters
Then the total length of increase = 28.8 cm
Then the increased length = (120 + 28.8) cm
= 148.8 cm
So the length becomes 148.8 cm after it is increased by 24%.