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Alona [7]
3 years ago
8

on Tuesday katy ran a mile inv8.34 minutes she ran another mile in 7.89 minutes on Wednesday what was the total time for both mi

les
Mathematics
2 answers:
Elden [556K]3 years ago
4 0
Katy ran a total of 11.23 miles on Wednesday 
asambeis [7]3 years ago
3 0
16.23
in this problem you basically add the minuets together such as 8.34+7.89.
Hope this helped=)
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The length of a rectangle is 3 feet less than twice the width of the rectangle. If the perimeter of the rectangle is 264 feet, f
Digiron [165]

L = 2w - 3

p = 264

2(L + w) = p

2(2w - 3 + w) = 264

2(3w - 3) = 264

6w - 6 = 264

6w = 270

w = 270/6

w = 90/2

w = 45

L = 2w - 3

L = 2(45) - 3

L = 90 - 3

L = 87

The length is 87ft, and the width is 45ft

7 0
2 years ago
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Can some help me with my homework it’s number 5. 6. 7. 8. And 9.
BaLLatris [955]

Answers:

5. 296

6. 479

7. 801

8. 920

9. $281

Step-by-step explanation:

For 5-8, you add the 2 numbers. Line up the numbers by their place value.

For 9, it says she starts with $233. She worked for 6 hours today. She makes $8 for every hour. First, you have to find how much she made today. 6 hrs times $8 for every hr is $48. In total, she has $281 because we added the amount she starts with, and the amount she earned today.

4 0
3 years ago
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What fraction is greter than 3 - 5
Julli [10]

Answer:

4/5 is greater

Step-by-step explanation:

7 0
2 years ago
After a college football team once again lost a game to their archrival, the alumni association conducted a survey to see if alu
valentina_108 [34]

Answer:

P-value for this hypothesis test is 0.00175.

Step-by-step explanation:

We are given that the alumni association conducted a survey to see if alumni were in favor of firing the coach.

A simple random sample of 100 alumni from the population of all living alumni was taken. Sixty-four of the alumni in the sample were in favor of firing the coach.

<u><em>Let p = proportion of all living alumni who favored firing the coach</em></u>

SO, Null Hypothesis, H_0 : p = 0.50   {means that the majority of alumni are not in favor of firing the coach}

Alternate Hypothesis, H_A : p > 0.50   {means that the majority of alumni are in favor of firing the coach}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                  T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p  = sample proportion of the alumni in the sample who were in favor of firing the coach = \frac{64}{100} = 0.64

            n = sample of alumni = 100

So, <em><u>test statistics</u></em>  =  \frac{0.64-0.50}{{\sqrt{\frac{0.64(1-0.64)}{100} } } } }

                               =  2.92

<u>Now, P-value of the hypothesis test is given by ;</u>

         P-value = P(Z > 2.92) = 1 - P(Z \leq 2.92)

                                             = 1 - 0.99825 = 0.00175

Therefore, the P-value for this hypothesis test is 0.00175.

4 0
3 years ago
You are taking a​ multiple-choice test that has 44 questions. each of the questions has 55 answer​ choices, with one correct ans
Aleks [24]
Since there are 55 choices, we have to have 55 options, and for 44 questions, we multiply how many options there are in 1 question by 44 to get 55*44=2420
6 0
3 years ago
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