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mart [117]
3 years ago
6

Analia is a school district manager. Here are some details about two schools in her district for the last school year:

Mathematics
1 answer:
seraphim [82]3 years ago
5 0
It’s b I hope that helps
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As it is an OR question though, you add them. 
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A student records the repair cost for 22 randomly selected dryers. A sample mean of $98.78 and standard deviation of $15.49 are
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Answer:

The critical value that should be used is T = 2.0796.

The 95% confidence interval for the mean repair cost for the dryers is between $91.912 and $105.648.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

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95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 21 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.0796, which is the critical value that should be used.

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.0796\frac{15.49}{\sqrt{22}} = 6.868

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The lower end of the interval is the sample mean subtracted by M. So it is 98.78 - 6.868 = $91.912

The upper end of the interval is the sample mean added to M. So it is 98.78 + 6.868 = $105.648

The 95% confidence interval for the mean repair cost for the dryers is between $91.912 and $105.648.

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2. What is an expression for the distance between the origin and a point P(x, y)?
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Answer:

Step-by-step explanation:

The answer is x=-4 the work is shown on the pic

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