Answer:
The percentage that of people who gave the movie a rating between 6.8 and 8.8
<em>P(6.8≤X≤8.8) = 83.9≅ 84 percentage</em>
Step-by-step explanation:
<u> Step(i):-</u>
Mean of the Population = 8.3 points
Standard deviation of the Population = 0.5 points
Let 'X' be the random variable in normal distribution
<em>Let X = 6.8</em>

Let X = 8.8

The probability that of people who gave the movie a rating between 6.8 and 8.8
<em>P(6.8≤X≤8.8) = P(-3≤Z≤1)</em>
= P(Z≤1)- P(Z≤-3)
= 0.5 + A(1) - ( 0.5 -A(-3))
= A(1) + A(3) (∵A(-3)=A(3)
= 0.3413 +0.4986 (∵ From Normal table)
= 0.8399
<u><em>Conclusion:-</em></u>
The percentage that of people who gave the movie a rating between 6.8 and 8.8
<em>P(6.8≤X≤8.8) = 83.9≅ 84 percentage</em>
Answer:
Step-by-step explanation:
![x^4+4x^3-27x-108\\=x^3(x+4)-27(x+4)\\=(x+4)(x^3-27)\\=(x+4)[x^3-3^3]\\=(x+4)(x-3)(x^2+3x+3)](https://tex.z-dn.net/?f=x%5E4%2B4x%5E3-27x-108%5C%5C%3Dx%5E3%28x%2B4%29-27%28x%2B4%29%5C%5C%3D%28x%2B4%29%28x%5E3-27%29%5C%5C%3D%28x%2B4%29%5Bx%5E3-3%5E3%5D%5C%5C%3D%28x%2B4%29%28x-3%29%28x%5E2%2B3x%2B3%29)
I Think The Answer Is 0.5 Or 5/10 But I'm Not Sure
Answer:
Step-by-step explanation:
28 -22 38 30 -4
-26 -8 -34 20 -16
-6 -34 -24 -20 24
38 -32 36 -34 32
John bought the TV for . . . . $1,900
John sold the TV for . . . . . $750
John lost this much on the TV . . . (1,900 - 750) = $1,150
What fraction of the amount he paid did he lose ?
$1,150 / $1,900 = 0.6053 of the amount he paid never came back
What is this fraction as a percentage ?
0.6053 = 60.53 %
Rounded to one decimal place: <em>60.5 % </em>
John took a beating on that TV. I hope he got a lot of good use out of it while he had it.