The original area of the rectangle is 
<u>Explanation:</u>
width = x
length = x + 2
area of the rectangle = x (x+2)
length = x + 2 + 5 = x+7

Solving this equation, we get
x =5ft
So, original width = 5ft
original length = 5+2ft = 7ft
Thus, original area of the rectangle = 5 X 7ft = 
Therefore, the original area of the rectangle is 
Answer:
Jed's Market
Step-by-step explanation:
Find out the cost of one candy bar for each store:
Smith's:
- 9.00 ÷ 3 = $3.00
Green's:
- 10.00 ÷ 4 = $2.50
Jed's:
- 12.00 ÷ 5 = $2.40
Wan's:
- It already tells you the price for each: $2.75
Finding the best deal:
- Look at all our costs per 1 candy bar. Which one has the smallest price?
- Because $2.40 is the smallest price, Jed's Market has the best buy.
I hope this helps!
Answer:
Option B and D
Step-by-step explanation:
Subtract 9 from both sides :
4x² + 4x - 8 = 0
Divide both sides by 4 :
x² + x - 2 = 0
Factorise using factorisation method :
x² - x + 2x -2 = 0
x(x - 1) +2(x-1) = 0
(x+2)(x-1) = 0
Solve for x
x +2 = 0 OR x - 1 = 0
x = -2 OR x = 1
Answer will be Option B and D
Hope this helped and have a good day
We want to find the values of a, b, c, and d such that the given matrix product is equal to a 2x2 identity matrix. We will solve a system of equations to find:
<h3>
Presenting the equation:</h3>
Basically, we want to solve:
![\left[\begin{array}{cc}-1&2\\a&1\end{array}\right]*\left[\begin{array}{cc}b&c\\1&d\end{array}\right] = \left[\begin{array}{cc}1&0\\0&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-1%262%5C%5Ca%261%5Cend%7Barray%7D%5Cright%5D%2A%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Db%26c%5C%5C1%26d%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%260%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D)
The matrix product will be:
![\left[\begin{array}{cc}-b + 2&-c + 2d\\a*b + 1&a*c + d\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-b%20%2B%202%26-c%20%2B%202d%5C%5Ca%2Ab%20%2B%201%26a%2Ac%20%2B%20d%5Cend%7Barray%7D%5Cright%5D)
Then we must have:
-b + 2 = 1
This means that:
b = 2 - 1 = 1
We also need to have:
a*b + 1 = 0
we know the value of b, so we just have:
a*1 + b = 0
Now the two remaining equations are:
-c + 2d = 0
a*c + d = 1
Replacing the value of a we get:
-c + 2d = 0
-c + d = 1
Isolating c in the first equation we get:
c = 2d
Replacing that in the other equation we get:
-(2d) + d = 1
-d = 1
Then:
c = 2d = 2*(-1) = -2
So the values are:
If you want to learn more about systems of equations, you can read:
brainly.com/question/13729904