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pshichka [43]
3 years ago
5

How to solve 3+5 (c+3)=-17

Mathematics
2 answers:
Natasha_Volkova [10]3 years ago
5 0
3+5(c+3)=−17

3+(5)(c)+(5)(3)=−17(Distribute)

3+5c+15=−17

(5c)+(3+15)=−17(Combine Like Terms)

5c+18=−17

Subtract 18 from both sides.

5c+18−18=−17−18

5c=−35

Divide both sides by 5.

5c/5=−35/5

c=−7

BlackZzzverrR [31]3 years ago
4 0
3 + 5(c + 3) = -17

First, subtract 3 from both sides. / Your problem should look like: 5(c + 3) = -17 - 3
Second, simplify -17 - 3 to get -20. / Your problem should look like: 5(c + 3) = -20
Third, divide both sides by 5. / Your problem should look like: c + 3 =  -\frac{20}{5}
Fourth, simplify \frac{20}{5} to 4. / Your problem should look like: c + 3 = -4
Fifth, subtract 3 from both sides. / Your problem should look like: c = -4 - 3
Sixth, simplify -4 - 3 to get -7. / Your problem should look like: c = -7

Answer: c = -7

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Read 2 more answers
ANSWER ALL (a-d) FOR 30 POINTS - EASY
djverab [1.8K]
Part a.

<span>The perimeter formula is: </span>P = 2w + 2L

Your answer for part A is P = 2w + 2L


Part b.

They tell us in part b, that:
w = 6L + 20

Substitute that into what we got for part a.

P = 2(6L + 20) + 2L
P = 12L + 40 + 2L
P = 14L + 40

Your answer for partb is P = 14L + 40


Part c.

So we take what we got from part b, and solve for L.

P = 14L + 40
14L = P - 40

L = \boxed{\frac{P-40}{14}}

That is your answer for part 3 ^


part d.

Plug in w = 32 into what we first got in part b.

w = 6L + 20
32 = 6L + 20
6L = 12

L = 2

Your answer for part d is L = 2

<span>:D</span>
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