Answer:
The width of the border can be 9 feet or 3.5 feet.
Step-by-step explanation:
Let the width be x
Length of room = 10 feet
Breadth of room = 15 feet
Length of rug = 10-2x
Breadth of rug = 15-2x
Area of rug =
We are given that the area of the rug is 24 square feet.
So,
---A






Substitute x =9 in A


LHS = RHS
Substitute x = 3.5


LHS = RHS
So, The width of the border can be 9 feet or 3.5 feet.
Answer:
2100
Step-by-step explanation:
There are 21 consonants that can serve as the first and last letters. There are 5 vowels that can serve as the 2nd and 4th letters. There are 20 remaining consonants that can serve as the 3rd letter. (The same consonant cannot appear in all three places.)
So, the total number of 5-letter palindromes that start with a consonant and alternate with a vowel will be ...
21×5×20 = 2100 . . . different palindromes
Answer:
7
Step-by-step explanation:
Its 7 because khan academy and i know it