Answer:
The relation is not a function
The domain is {1, 2, 3}
The range is {3, 4, 5}
Step-by-step explanation:
A relation of a set of ordered pairs x and y is a function if
- Every x has only one value of y
- x appears once in ordered pairs
<u><em>Examples:</em></u>
- The relation {(1, 2), (-2, 3), (4, 5)} is a function because every x has only one value of y (x = 1 has y = 2, x = -2 has y = 3, x = 4 has y = 5)
- The relation {(1, 2), (-2, 3), (1, 5)} is not a function because one x has two values of y (x = 1 has values of y = 2 and 5)
- The domain is the set of values of x
- The range is the set of values of y
Let us solve the question
∵ The relation = {(1, 3), (2, 3), (3, 4), (2, 5)}
∵ x = 1 has y = 3
∵ x = 2 has y = 3
∵ x = 3 has y = 4
∵ x = 2 has y = 5
→ One x appears twice in the ordered pairs
∵ x = 2 has y = 3 and 5
∴ The relation is not a function because one x has two values of y
∵ The domain is the set of values of x
∴ The domain = {1, 2, 3}
∵ The range is the set of values of y
∴ The range = {3, 4, 5}
The annnnnssssssswer is c
Answer:
We conclude that:
h(f(-1)) = -2
∴ option D i.e. -2 is correct.
Step-by-step explanation:
Given
f(x) = 4x² - 1
g(x) = 1/2x + 5
h(x) = 2(x - 4)³
To determine
h(f(-1)) = ?
In order to determine h(f(-1)) first we need to determine f(-1).
substitute x = -1 in the function f(x) = 4x² - 1
f(-1) = 4(-1)² - 1
f(-1) = 4(1) - 1
f(-1) = 4-1
f(-1) = 3
so
h(f(-1)) = h(3)
now substitute h = 3 in the function h(x) = 2(x - 4)³
h(x) = 2(x - 4)³
h(3) = 2(3 - 4)³
h(3) = 2(-1)³
h(3) = 2(-1)
h(3) = -2
Thus,
h(f(-1)) = h(3) = -2
Hence, we conclude that:
h(f(-1)) = -2
∴ option D i.e. -2 is correct.
Answer:
5r
Step-by-step explanation:
(8r + 5) - (3r + 5)
8r + 5 - 3r - 5
5r
Answer:
The president is using the mode because it is the most obvious answer. The fans are using the iconic mean which is the middle number of the data set. They can be different because different people think of numbers differently.
Step-by-step explanation:
