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qwelly [4]
3 years ago
11

That are the greatest common factors of 16 28 and 48

Mathematics
2 answers:
egoroff_w [7]3 years ago
5 0
The answer is 4 because 4x4 is 16 4x7 is 28
4x12 is 48 they all start wit 4
ira [324]3 years ago
3 0

Answer:

4

Step-by-step explanation:

The factors of 16 are:1 2 4 8 16

the factors of 28 are:1 2 4 7 14 28

the factors of 48 are: 1 2 3 4 6 8 12 16 24 48

and so the common factors are :1 2 4 the greatest one is 4 and so the answer is 4

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Will someone please help me understand how to graph y ≤ 1 – 3x please show step by step
rjkz [21]
Change the equation to y=-3x+1. this means the slope is -3, and the y intercept is 1. the line is dashed, and the area below the line is shaded.
6 0
3 years ago
a sequence has a first term of 2 and a constant ratio of _3/2 what are the first five terms of the sequence
soldi70 [24.7K]
This is a geometric sequence with a=2, r= -3/2.
Therefore,
a₁ = 2
a₂ = 2*(-3/2) = -3
a₃ = 2*(-3/2)² = 9/2 = 4.5
a₄ = 2(-3/2)³ = -27/4 = -6.75
a₅ = 2(-3/2)⁴ = 81/8 = 10.125

Answer:
In fractions, the first five terms are
     2, -3, 9/2, -27/4, 81/8
In decimals, the first five terms are
     2.000, -3.000, 4.500, -6.750, 10.125


5 0
3 years ago
Lee Middle School orders 15 textbooks for every 12 students. The table shows how many textbooks the school orders for certain nu
Mariulka [41]

Answer: 90 textbooks


Step-by-step explanation:

everytime you multiply the number of students you multiply the books by the same number. to find how many times 72 was multiplied you divide it by 12.

72 ÷ 12 = 6

then multiply the original number of books (15) by 6.

15 * 6 = 90

so for every 72 students the school orders 90 textbooks

5 0
3 years ago
a store had a sale to celebrate veterans day. Every item in the store is advertised as 1/5 off the original price. If an item is
makkiz [27]

Answer:

$175

Step-by-step explanation:

let the original price be x

if 1/5 is off the price then the sells is at 4/5

4/5 of x = 140

thus,

4/5* x=140

4x = 140*5

x=700/4

x=$175

3 0
2 years ago
Find the midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9)
JulsSmile [24]

The midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9) is \left(\frac{-9}{2}, \frac{-3}{2}\right)

<u>Solution:</u>

Given, two points are (-6, 6) and (-3, -9)

We have to find the midpoint of the segment formed by the given points.

The midpoint of a segment formed by \left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { and }\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right) is given by:

\text { Mid point } \mathrm{m}=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)

\text { Here in our problem, } x_{1}=-6, y_{1}=6, x_{2}=-3 \text { and } y_{2}=-9

Plugging in the values in formula, we get,

\begin{array}{l}{m=\left(\frac{-6+(-3)}{2}, \frac{6+(-9)}{2}\right)=\left(\frac{-6-3}{2}, \frac{6-9}{2}\right)} \\\\ {=\left(\frac{-9}{2}, \frac{-3}{2}\right)}\end{array}

Hence, the midpoint of the segment is \left(\frac{-9}{2}, \frac{-3}{2}\right)

6 0
3 years ago
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