Answer:
Perimeter of quadrilateral will be
Step-by-step explanation:
Given quadrilateral is a reflection of quadrilateral over the line .
So, all the corresponding sides of both the quadrilateral should be equal.
Also, we can see from the diagram that
As both image are reflection of same scale we can add corresponding sides.
So, the perimeter of will be
And we have
Now, perimeter of will be
Perimeter of quadrilateral is
Answer: 2 - 2*sin³(θ) - √1 -sin²(θ)
Step-by-step explanation: In the expression
cos(theta)*sin2(theta) − cos(theta)
sin (2θ) = 2 sin(θ)*cos(θ) ⇒ cos(θ)*2sin(θ)cos(θ) - cos(θ)
2cos²(θ)sin(θ) - cos(θ) if we use cos²(θ) = 1-sin²(θ)
2 [ (1 - sin²(θ))*sin(θ)] - cos(θ)
2 - 2sin²(θ)sin(θ) - cos(θ) ⇒ 2-2sin³(θ)-cos(θ) ; cos(θ) = √1 -sin²(θ)
2 - 2*sin³(θ) - √1 -sin²(θ)
The solution of the equation x2+7x is 0, -7 using the quadratic formula.
Step-by-step explanation:
x2 + 7x = 0
-b ± √
b2 - 4(ac)/ 2a
substitution,
a = 1, b = 7, c = 0
= -7 ± √(7)2 - 4(1 x 0) / 2 x 1
= - 7
± 7 / 2
x = 0 , -7
Must be in the same units
6 ft/ 24 ft (8yds x 3 = 24 ft)
Let's use yards instead
6 ft = 2 yds
so
2 yds/8 yds again is 1/4
2 divided by 7 would give you 29%