Answer:
The answer is B
Step-by-step explanation:
Answer:
14 degrees
Step-by-step explanation:
Complementary angles means they add up to 90 degrees.
If the smaller angle times 5 plus 6 equals the bigger angle, then:
14 x 5 = 70
70 + 6 = 76
76 + 14 = 90
Consider the top half of a sphere centered at the origin with radius

, which can be described by the equation

and consider a plane

with

. Call the region between the two surfaces

. The volume of

is given by the triple integral

Converting to polar coordinates will help make this computation easier. Set

Now, the volume can be computed with the integral

You should get
Answer:
the first one on the bottom
Step-by-step explanation:
There is a little trick to find out if it is a function or not. This trick is called the vertical line test. if you can scan the figure with a virtual line and it does not touch more than one side of the figure at one time then it is a function. if it touches more than one side or line of the figure it is not a function.
Answer:
The relation is 
Step-by-step explanation:
x and y are directly proportional:
This means that the equation is given by:

In which a is the multiplier that relates these two variables.
x= -4, y =6
We use this to find a. So




So
The relation is 