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3 years ago

12

Help Please (I needed 20 characters)

1 answer:

liq [111]3 years ago

4 0

Is a (0,18) ? not sure though baha.

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jacks car used 18 gallons of gasoline to go for 68 miles at that rate how many gallons would be used to go 754 miles

anygoal [31]

41.88 (repeated) gallons of gad

8 0

3 years ago

Answer correctly please ASAP!

Serggg [28]

10 1/2 ft=2x-18 in

convert ft to in--10 1/2ft=126 in

126=2x-18

2x=144

x=<em>72 inches or 6 feet</em>

5 0

3 years ago

The base of the triangle decreases by 30% and the height increases by 20%.

sergeinik [125]

Answer:

Area decreases by 16%

Step-by-step explanation:

Use formula for the area of the triangle

$A=\dfrac{1}{2}\cdot \text{Base}\cdot \text{Height}$

<u>Initial triangle:</u>

The base is 18 cm

The height is 5 cm

The area is

$A_{initial}=\dfrac{1}{2}\cdot 18\cdot 5=45\ cm^2$

<u>New triangle:</u>

The base is $(1-0.3)\cdot 18=0.7\cdot 18=12.6\ cm$

The height is $(1+0.2)\cdot 5=1.2\cdot 5=6\ cm$

The area is

$A_{new}=\dfrac{1}{2}\cdot 12.6\cdot 6=37.8\ cm^2$

Area decreases by

$100\%-\dfrac{37.8}{45}\cdot 100\%=100\%-84\%=16\%$

5 0

3 years ago

If U = {all positive integers} and A = {x|x ∈ U and x is an odd positive integer}, which describes Ac?

tekilochka [14]

The answer is:

D. Ac = {xΙx ∈ U and is an even positive integer}

:)

6 0

4 years ago

Read 2 more answers

Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

7 0

3 years ago