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erma4kov [3.2K]
4 years ago
15

Let 3x^2+kx+4. determine all values of k such that the quadratic equation f(x) =0 has one real root

Mathematics
1 answer:
user100 [1]4 years ago
7 0
//I'll use the discriminant rule for this.
b^2 - 4ac = 0 when one real root

Therefore, k^2 - 4*3*4= 0
k^2 = 48
k= +-4√3
You might be interested in
7c - 7 = 4c + 17 *has to show work*
Nina [5.8K]
7c-7=4c+17
7c-4c=17+7
3c=24
c=24/3=8
6 0
3 years ago
Sb plz help not much a lot of points!!!!! Plz help
Tatiana [17]

Answer:

10 months

Step-by-step explanation:

22x+80=30x

subtract both sides by 30x

-8x+80=0

then subtract 80 from both sides

−8x=−80

divide both sides by -8

x=10

8 0
3 years ago
Read 2 more answers
Convert the following mixed numbers to decimals and find the sum. 6 5/8 + 2 3/4.
Elena-2011 [213]

Answer:

9.38

Step-by-step explanation:

6 5/8 + 2 3/4=6.625+2.75

9.38

6 0
3 years ago
A worker has job offers from two companies. The information below summarizes the job offer from each company.Company A:Starting
Zanzabum

Using linear functions, we have that:

A.

For Company A: S_A(n) = 31000 + 3000n

For Company B: S_B(n) = 38000 + 2000n

B. The salaries will be the same after 7 years.

A linear function is given by:

y = mx + b

In which:

  • m is the slope, which is the rate of change.
  • b is the y-intercept, which is the initial value.

Item a:

  • For Company A, the salary starts at $31,000, with a raise of $3,000 each year. Thus, b = 31000, m = 3000, and the salary after n years is given by:

S_A(n) = 31000 + 3000n

  • For Company B, the salary starts at $38,000, with a raise of $2,000 each year. Thus, b = 38000, m = 2000, and the salary after n years is given by:

S_B(n) = 38000 + 2000n

Item b:

  • They will be the same after n years, for which:

S_A(n) = S_B(n)

Then

31000 + 3000n = 38000 + 2000n

1000n = 7000

n = \frac{7000}{1000}

n = 7

The salaries will be the same after 7 years.

A similar problem is given at brainly.com/question/24282972

7 0
2 years ago
Solve this problem out
Virty [35]

Option C

When (2x - 3)^2 is subtracted from 5x^2 then the result is x^2 + 12x - 9

<h3><u>Solution:</u></h3>

Given that (2x - 3)^2 is subtracted from 5x^2

We have to find the result

Subtraction is a mathematical operation that tells us the difference between two numbers.

When "a" is subtracted from "b", we write in mathematical expression as "b - a"

So (2x - 3)^2 is subtracted from 5x^2 is written mathematically as:

\rightarrow 5x^2 - (2x - 3)^2

<em><u>Expanding the above expression using algebraic identity:</u></em>

(a-b)^2 = a^2 - 2ab + b^2

\rightarrow 5x^2 - ((2x)^2 -2(2x)(3) + (3)^2)\\\\\rightarrow 5x^2 - (4x^2 - 12x + 9)

Multiplying the nnegative sign with terms inside bracket

<em><u>There are two simple rules to remember: </u></em>

  • When you multiply a negative number by a positive number then the product is always negative.
  • When you multiply two negative numbers or two positive numbers then the product is always positive.

\rightarrow 5x^2 - (4x^2 - 12x + 9)\\\\\rightarrow 5x^2 - 4x^2 + 12x -9\\\\\rightarrow x^2 + 12x - 9

Hence the result is: x^2 + 12x - 9

3 0
3 years ago
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