Answer:
I believe the answer would be D) Indian ocean.
Explanation:
The Indian Ocean lies between the continents of Africa, Asia, and Australia.
Here's a nice little image of some arrows I drew on a map to show that it is indeed south of Asia and between Africa and Australia:
CAH stands for CosineФ = Adjacent ÷ Hypotenuse.
TOA stands for TangentФ = Opposite ÷ Adjacent.
Hence,
SineФ = Opposite ÷ Hypotenuse
Substituting the values:
Sine35° = x ÷ 12
0.5735 = x ÷ 12
x = 0.5735 × 12
x = 6.88 (rounded to the nearest hundredth)
Q6: Given the shape attached, therefore, using the triangle given, we have:
Hence,
CosineФ = Adjacent ÷ Hypotenuse
Substituting the values:
Cos54° = x ÷ 30
0.5877 = x ÷ 30
x = 0.5877 × 30
x = 17.63 (rounded to the nearest hundredth)
Q7: Given the shape attached, therefore, using the triangle given, we have:
Hence,
TangentФ = Opposite ÷ Adjacent
Substituting the values:
tan22° = x ÷ 85
0.4040 = x ÷ 85
x = 0.4040 × 85
x = 34.34 (rounded to the nearest hundredth)
Q8: Given the shape attached, therefore, using the triangle given, we have:
Angle of elevation = 16°
length of the opposite side to the angle = x
Length of Hypoteneus = 14
Calculations:
Using the SOH CAH TOA rules:
Hence,
CosineФ = Adjacent ÷ Hypotenuse
Substituting the values:
Sine16° = x ÷ 14
0.2756 = x ÷ 14
x = 0.2756 × 14
x = 3.86 (rounded to the nearest hundredth)
Q9: Given the shape attached, therefore, using the triangle given, we have:
TangentФ = Opposite ÷ Adjacent
Substituting the values:
tan65° = x ÷ 9
2.1445 = x ÷ 9
x = 2.1445 × 9
x = 19.30 (rounded to the nearest hundredth)
Q10: Given the shape attached, therefore, using the triangle given, we have:
Angle of elevation = 51°
length of the adjacent side to the angle = x
Length of Hypoteneus = 70
Calculations:
Using the SOH CAH TOA rules:
Hence,
CosineФ = Adjacent ÷ Hypotenuse
Substituting the values:
Cos51° = x ÷ 70
0.6293 = x ÷ 70
x = 0.6293 × 70
x = 44.05 (rounded to the nearest hundredth)
Q11: Given the shape attached, therefore, using the triangle given, we have:
Angle of elevation = 36°
length of the opposite side to the angle = 15
Length of Hypoteneus = x
Calculations:
Using the SOH CAH TOA rules:
Hence,
CosineФ = Adjacent ÷ Hypotenuse
Substituting the values:
Sine36° = 15 ÷ x
0.5877 = 15 ÷ x
x = 15 ÷ 0.5877
x = 25.52 (rounded to the nearest hundredth)
Q12: Given the shape attached, therefore, using the triangle given, we have:
Hence,
TangentФ = Opposite ÷ Adjacent
Substituting the values:
tan65° = 100 ÷ x
2.1445 = 100 ÷ x
x = 100 ÷ 2.1445
x = 46.63 (rounded to the nearest hundredth)
Q13: When a 25-ft ladder is leaned against a wall, it makes a 72° with the ground. How high up on wall does the ladder reach?
The angle of elevation from the ground = 72°
length of the wall opposite to the angle = X
Length of ladder (Hypoteneus) = 25 feet
Calculations:
Using the SOH CAH TOA rules:
Hence,
SineФ = Opposite ÷ Hypotenuse
Substituting the values:
Sine72° = x ÷ 25
0.9510 = x ÷ 25
x = 25 ÷ 0.9510
x = 23.77 (rounded to the nearest hundredth)
ANSWERS TO QUESTION 14 AND 15 ARE ATTACHED
