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sertanlavr [38]
3 years ago
15

Evaluate X + Y when X = 13.1 and Y = 2.2 A. 10.9 B. -10.9 C. 35.1 D. 15.3

Mathematics
1 answer:
bazaltina [42]3 years ago
4 0
<span>X +Y = 13.1 +  2.2
= 15.3

answer
</span><span>D. 15.3</span>
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Answer:

D is the correct a

Step-by-step explanation:

From table A-3: Areas under the normal curve

we can deduce that k=0.9

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2 years ago
A human heart beats an average of 80 beats per minute. How many beats is this in an hour?
Aleksandr [31]

Answer:

4800 beats an hour

Step-by-step explanation:

there are 60 minutes in and hour

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Carlos wrote the number 52,700,000 in scientific notation. Which number did he write?
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2 years ago
Answer these three questions for 100 points
pochemuha

Answer: C, A, D

edit - sorry the title was wrong earlier

Step-by-step explanation:

Question 1

in the quadratic formula, the equation is in the format of ax^2 + bx + c

so rearrange this equation so all values are on one side

-6x^2 = -9x + 7

-6x^2 + 9x - 7 =0

so a = -6, b = 9, c = -7

answer = C

Question 2

note that all the values are already on one side for this, so repeat the process from question 1 where the equation is in the format of ax^2 + bx + c

the equation = −6x2 − 8x + 12 = 0

so a = -6, b = -8, c = 12

answer = A

Question 3

(see picture below for steps)

following the same process above, a = 4, b = 45, and c = 24, so plug these values in the quadratic equation shown in the picture below

so you get the answers x = -10.69 and x = -0.56 after putting them in a calculator

answer = D

8 0
3 years ago
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Basic Computation: Testing M1 2 M2 A random sample of 49 measurements from a population with population standard deviation 3 had
Elenna [48]

Answer:

The sample statistics follows a standard normal distribution since the sample size are large enough.

Step-by-step explanation:

Given that:

<u>First population:</u>

Sample size n_1 = 49

Population standard deviation \sigma_1  = 3

Sample mean \overline x _1= 10

<u>Second population:</u>

Sample size n_2 = 64

Population standard deviation \sigma_2= 4

Sample mean \overline x_2= 12

The sample statistics follows a standard normal distribution since the sample size are large enough.

The null and alternative hypotheses can be computed as:

\mathbf{H_o:\mu_1=\mu_2}

\mathbf{H_1:\mu_1\ne\mu_2}

Level of significance  = 0.01

Using the  Z-test statistics;

Z = \dfrac{\overline x_1 - \overline x_2}{\sqrt{\dfrac{\sigma_1^2}{n_1} + \dfrac{\sigma_2^2}{n_2}}}

Z = \dfrac{10- 12}{\sqrt{\dfrac{3^2}{49} + \dfrac{4^2}{64}}}

Z = \dfrac{-2}{\sqrt{\dfrac{9}{49} + \dfrac{16}{64}}}

Z = \dfrac{-2}{\sqrt{0.18367 +0.25}}

Z = \dfrac{-2}{\sqrt{0.43367}}

Z = \dfrac{-2}{0.658536}

Z = - 3.037

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The P-value = 2P (z < -3.04)

From the z tables

= 2 × (0.00118)

= 0.00236

Thus, since P-value is less than the level of significance, we fail to reject the null hypotheses H_o

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2 years ago
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