It snowed 875 inches last winter. This was 5 times the amount that it snowed the previous winter. How much did it snow the previ
1 answer:
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Answer:
See attached photo for graph
Step-by-step explanation:
Solve the equation for y... (that means get y by itself)
4y = -5x - 6 (subtract 5x from both sides)
y = -(5/4)x - 6/4 (divide both sides by 4)
y = -(5/4)x - 3/2 (simplify)
Now you can graph using slope-intercept method. The y-intercept is -3/2, and the slope is -5/4
Answer:
Perpendicular
Step-by-step explanation:
Parallel lines mean lines that have same slope but since both equations have different slopes which you can check by looking at m-value in y = mx + b. In this case m1 or first slope is -4/3 and m2 or second slope is 3/4.
Perpendicular means that both lines are reciprocal to each other. This means the perpendicular condition is or satisfies
We have m1 = -4/3 and m2 = 3/4.
Therefore, -4/3 * 3/4 = -1 thus both lines are perpendicular to each other as it satisfies m1m2 = -1 condition.
<u>Question Completion</u>
(a)What is your null hypothesis?
(b)What is your expected phenotypic ratio based on Mendelian inheritance?
(c)Calculate the expected number of flowers you should have gotten based on the Mendelian inheritance. Then calculate a chi-square value, degrees of freedom, and a p-value.
- Chi-square statistic: _____
- Degrees of freedom (# phenotypes -1):
- P-value:
(d)Interpret your results. Do you reject it or fail to reject your null hypothesis (please restate the null)?
Answer:
(a)
(b)9:3:3:1
(c)
- Chi-square statistic: 3.8914
- Degrees of freedom (# phenotypes -1) =3
- P-value: 0.2734
(d)We fail to reject the null hypothesis.
Step-by-step explanation:
In the flowering plant, white flowers (B) are dominant over red flowers (b), and short plants (E) are dominant over tall flowers (e). An F2 generation was created by crossing two F1 individuals (each BbEe).
(a)The null hypothesis is:
(b)The gametes are BE, Be, bE and be.
The offsprings are presented in the table below:
The expected phenotypic ratio based on Mendelian inheritance
BE:Be:bE:be=9:3:3:1
(c)
Therefore:
- Chi-square statistic: 3.8914
- Degrees of freedom (# phenotypes -1): 4-1 =3
- P-value: 0.2734
(d) Our null hypothesis is:
Since p>0.05, the given data fit the predicted phenotypic ratio.
We, therefore, fail to reject the null hypothesis.
The difference in the observed and expected are sosmall that they can be attributed to random chance.