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Varvara68 [4.7K]
3 years ago
15

F(x) = 9x2 - 4 Find the zeros of the function

Mathematics
1 answer:
Delvig [45]3 years ago
4 0

Answer:

I believe that the answer is 14.

Step-by-step explanation:

hope it helped

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Lisa sale de su casa y recorre su ruta a una velocidad de 1.15m/s, que ten
Gnoma [55]

No entiendo española

8 0
3 years ago
Suppose you add two vectors A and B . What relative direction between them produces the resultant with the greatest magnitude? W
Anna71 [15]

Answer: The resultant would be the sum and the difference between the vectors.

Step by step explanation: 1. The possible resultant is between the sum of the 2 vectors and the difference between the two vectors.

2. The greatest magnitude is when the vectors lie in the same direction and the sum would be the scalar sum of the two vectors. The angle between the two would be zero degree.

6 0
3 years ago
Teresa graphs the following 33 equations: y=2xy=2x, y=x2+2y=x2+2, and y=2x2y=2x2. She says that the graph of y=2xy=2x will event
Neko [114]
The correct question is 
<span>Teresa graphs the following 3 equations: y=2x, y=x2+2, and y=2x2. She says that the graph of y=2x will eventually surpass both of the other graphs. Is Teresa correct? Why or why not?

we have that
y=2x
y=x</span>²+2
y=2x²

using a graph tool
see the attached figure

<span>We can affirm the following
</span>the three graphs present the same domain-----> the interval (-∞,∞)

The range of the graph y=2x  is the interval (-∞,∞)

The range of the graphs y=x²+2 and y=2x² is the interval [0,∞)

therefore
<span>Teresa is not correct because the graph of y = 2x will not surpass the other two graphs since in the interval of [0, infinite) the three graphs present the same range</span>

3 0
4 years ago
The points A-1,-9) and K(5,1) are endpoints of a diameter of circle 5. Which equation represents circle S?
Lilit [14]

Answer:

A

Step-by-step explanation:

if (x1,y1) and (x2,y2) are the extremities of diameter,then eq. of circle is

(x-x1)(x-x2)+(y-y1)(y-y2)=0

reqd. eq. is (x+1)(x-5)+(y+9)(y-1)=0

x^{2} +x-5x-5+y^2+9y-y-9=0\\x^{2} -4x+y^2+8y-14=0\\compare with x^2+y^2+2gx+2fy+c=0\\center (-g,-f) \\radius r=\sqrt{g^2+f^2-c}

center is (2,-4)

r=√(2²+(-4)²-(-14))

=√(4+16+14)

=√(34)

eq. of circle is (x-2)²+(y+4)²=34

or

(x²-4x)+(y²+8y)=14

(x²-4x+4)+(y²+8y+16)=14+4+16

(x-2)²+(y+4)²=34

4 0
3 years ago
Solve the following equation for 0°≤x≤360° : 2 cot 2x + 3 = 0
evablogger [386]

Answer:

π

2

,

3

⋅

π

2

,

3

⋅

π

4

,

7

⋅

π

4

Explanation:

Factorizing your equation we get

cot

(

x

)

=

0

so

cos

(

x

)

=

0

we get the following Solutions in the given interval

x

=

π

72

or

x

=

3

π

2

for the second case we get

cot

(

x

)

=

−

1

so

cos

(

x

)

=

−

sin

(

x

)

and we get

x

=

3

π

4

or

x

=

7

π

4

Hint:

To get the Solutions of the last equation you can use

√

sin

(

x

+

π

4

)

=

0

Step-by-step explanation:

3 0
3 years ago
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