hey big jerry your answer will be m > 2
|m|-2>0
m-2>0
m > 2
Answer:the horizontal displacement is 34.64 meters
The maximum height is 15 meters
Step-by-step explanation:
As the ball moves from the ground at 30 degrees, it travels through a parabolic path. It can therefore be likened to a projectile. The horizontal displacement to where it lands is the range. The formula for determining range,R is
R = U^2Sin2#)/g
Where
U represents the initial velocity of the ball
g is acceleration due to gravity
# represents the angle above the horizontal.
From the information given
# = 30 degrees
U = 20 m/s
g = 10m/s^2
R = 20^2Sin2×30)/10 = (400Sin60)/20 = (400×0.8660)/10
= 34.64 meters
To determine the maximum height of the ball, H,
H = (U^2Sin^2#)/2g
H = (20^2 × Sin^2 30)/2×10
H = (400 × 0.866^2)/20 = 15 meters
Answer:
60°
Step-by-step explanation:
In an equilateral triangle, the angles are also all equal. Since the sum of angles of a triangle is 180°, each of the angles is ...
(1/3)×180° = 60°
Answer:
The real answer is 6
Step-by-step explanation:
Fairly simple. You know the length and the area, but you don't know the width. So your equation looks like this: 30 x ? = 180. But to figure out the width, you change the position of the numbers in the equation like this:
180 ÷ 30 = ?. Then you solve. 180 ÷ 30 = 6. If you want to double check your answer, you can plug in your answer to your original equation, 30 x 6 = 180.
Hope this helps!
Answer:
33.6
you are welcome :)
Step-by-step explanation:
