The length of OM is 4/3 the length of OJ, and the length of ON is 4/3 the length of OK. Thus, two pairs of sides from the triangles are proportional to each other.
Also, angle O from one of the triangles is equal to angle O of the other triangle because they are the same angle.
Thus, the two triangles are similar by SAS (side-angle-side) similarity theorem. This theorem is quite similar to the SAS congruence theorem.
To make a similarity statement, we just have to match corresponding parts when naming the triangle.
Similarity statement: ΔOJK~ΔOMN
Answer:
x ≠ 4 or -2
Step-by-step explanation:
the denominator cannot be zero, so factor the bottom equation to get the zeros and those are the domain restrictions.
3x^2 - 6x - 24 ≠ 0
3(x^2 - 2x - 8) ≠ 0 (factor out a 3)
3(x - 4)(x + 2) ≠ 0 (factor equation)
x ≠ 4, x ≠ -2 (use zero product property to find zeros)
Hello,
tan t /(sec t -cos t)= sin t/(cos t *(1/cos t -cos t))
=sin t/(cos t*(1-cos ²t)/cos t))
=sin t/sin² t=1/sin t [or=cosec t.]
Answer:
x : 32 = 9 : 4
4x = 288
x = 72
Step-by-step explanation:
