please need help ASAP A discount book store sells hardcover books for $8 each and paperbacks for $4 each.The number of hardcover
books, h, sold one day was 2 more than four times the number of paperback books, p, sold that same day. The total amount of sales for that day was $160. Jean-Paul wrote the following system of linear equations to find the number of each type of book sold. 8H+4P=160 P4H+2 what was paul's error
Translate every statement into algebraic language.
1) <span>hardcover
books for $8 each
- name h the number of hardcover books - amount of sale from hardcover books = 8h
2) paperbacks for $4 each
- namel p the number from paperback
books - amount of sale of paperbacks = 4p
3) the number of hardcover books, h, sold one day was 2 more than four times the number of
paperback books, p, sold that same day.
- h = 2 + 4p
4) the total amount of sales for
that day was $160.
- 8h + 4p = 160
6) system of equations
h = 2 + 4p 8h + 4p = 160
5) Jean-Paul wrote the following system of linear
equations to find the number of each type of book sold, </span><span>
8H+4P=160 P=4H+2
<---------- here is the error. This means that number of paperback books sold was 2 more than four times the number of hardcover books sold, when the right statement is that </span><span><span>the number of hardcover book sold was 2 more than four times the number of
paperback books, p, sold.</span></span>
The formula required is: where A is the amount after t years of the principal P invested at an annual interest rate r (expressed as a decimal fraction) compounded n times per year. Plugging in the given values, we get: The final amount is $22,096.17
