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Alchen [17]
4 years ago
12

If a bag has 40 red and blue marbles and a quarter of them are red what is the probability of picking a blue one

Mathematics
1 answer:
ella [17]4 years ago
7 0
Total marbles = 40 & 1/4  (or 0.25) are, then RED = 40x 0.25 = 10

If RED = 10 then BLUE = 30

P(picking one blue) = 30/40 = 3/4 =0.75
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18 and 52 are the two numbers
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Can someone please help me on this question <br> I will give brainliest
xz_007 [3.2K]

Answer:

A) 3 in

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Geometry</u>

  • Surface Area of a Sphere: SA = 4πr²
  • Diameter: d = 2r

Step-by-step explanation:

<u>Step 1: Define</u>

SA = 23 in²

<u>Step 2: Find </u><em><u>r</u></em>

  1. Substitute [SAS]:                    23 in² = 4πr²
  2. Isolate <em>r </em>term:                         23 in²/(4π) = r²
  3. Isolate <em>r</em>:                                  √[23 in²/(4π)] = r
  4. Rewrite:                                   r = √[23 in²/(4π)]
  5. Evaluate:                                 r = 1.35288 in

<u>Step 3: Find </u><em><u>d</u></em>

  1. Substitute [D]:                    d = 2(1.35288 in)
  2. Multiply:                              d = 2.70576 in
  3. Round:                                d ≈ 3 in
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3 years ago
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Alona [7]

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Explanation:

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6 0
3 years ago
Find the 81st term of the arithmetic sequence -28,-34,-40
VLD [36.1K]

Answer

sequence -28,-34,-40

1st term = -28

comman difference = -34 - (-28) = -6

comman term = a + (n-1)d

a= first term

d= difference

comman term = a + (n-1)d

                       = -28 + (n-1)(-6)

                       = -28 -6n +6

                       = -22-6n

1st term --> n =1 = -22 -6.1 =  -22 -6 =-28

2nd term --> n =2 = -22 -6.2 =  -22 -12 =-34

81st term --> n =81 = -22 -6.81 =  -22 -486 = -508

Step-by-step explanation:

8 0
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