To solve the system of equations you have to cancel out a variable. I chose to cancel out Y. First, the coefficients of y need to be the same in both equations. To do this multiply to the top equation by 2 so you get

2(2x) +2(y) = 2(-6)

4x + 2y = -12

Next, subtract the second equation from the first to cancel out the y’s

4x + 2y =-12

-(-8x + 2y = -12)

————————

12x = -24

Solve

X = -24/12

X=-2

Plug x into the original equation to find y

2(-2) + y = -6

-4 + y = -6

Y = -6 +4

Y=-2

You can substitute x and y into the original equations to double check

3 0

3 years ago

12 – 2x= -2(y – x) -2x = -2(y – x) – 12 x= (y - x) + 6

Vilka [71]

Answer:

x=o and y= -6

Step-by-step explanation:

12-2x = - 2(y-x)

or,12-2x = -2y + 2x

or, 12 = - 2y + 4x

or, 12/2= 2x - y

or, 2x - y = 6

• 2x -6= y.....eqn_1

-2x=-2y+2x -12

or,4x +2y= -12

or,4x + 2(2x-6)= -12

or, 4x+4x-12=-12

or, 8x= 0

• x= o

putting the value of x in eqn...3

o=(y-0)+6

or, o= y + 6

•y = -6

5 0

3 years ago