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Ede4ka [16]
3 years ago
11

Write the following radical expression as a rational exponent: (∛m4)8. Write your rational exponent in simplest form.

Mathematics
1 answer:
Luden [163]3 years ago
3 0

(\sqrt[3]{m^4})^8= (m^\frac{4}{3})^8=m^\frac{32}{3}

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Simplify.<br><br> 38√<br><br><br><br><br> 3√4<br><br> 6√8<br><br> 24√8<br><br> 6√4
Naya [18.7K]

Answer:

the first one i believe

Step-by-step explanation:

hope this helps

5 0
3 years ago
Find the value of x in 4:x::x:16
AnnyKZ [126]

Given:

4:x::x:16

To find:

The value of x.

Solution:

We have,

4:x::x:16

It means, we have

4:x = x:16

It can be rewritten as

\dfrac{4}{x}=\dfrac{x}{16}

On cross multiplication, we get

4\times 16=x\times x

64=x^2

Taking square root on both sides.

\pm \sqrt{64}=x

\pm 8=x

Since ratio can be negative or positive, therefore, the value of x is either -8 or 8.

4 0
2 years ago
Please please please help me!!!!!!
soldier1979 [14.2K]

Answer:

Step-by-step explanation:

Use Pythagorean theorem.

c^2 = a^2+b^2

c^2 = 4^2+6^2

c^2 = 16+36

c^2 = 52

c = √52 = 7.21

7 0
3 years ago
One uranium atom has a mass of 3.95 x 10^-22 grams.
creativ13 [48]
Remember
(ab)/(cd)=(a/c)(b/d)
and
\frac{x^n}{x^m}=x^{n-m}

1kg=1000g=1*10^3g
hmm, I estimate, 4 of them

x=number of attoms
mass of 1 times x=1*10^3
3.95*10^-22 times x=1*10^3
divide both sides by 3.95*10^-22
x=\frac{1*10^3}{3.95*10^{-22}}= (\frac{1}{3.95}  )( \frac{10^{3}}{10^{-22}} )=0.25316*10^{25}=2.5316*10^{24}
a million has 9 zeroes
so 24 zeroes is alot that is a <span>septillion, so there are 2.5316 septillion uranium atoms in 1kg


a. 4
b. underestimate

</span>
5 0
3 years ago
If $240 is invested at an interest rate of 9% per year and is compounded monthly, how much will the investment be worth in 14 ye
Nesterboy [21]

FV=(240)[1+(0.09/12)]^(12*14]

=(240)[1+0.0075]^168

=(240)(3.5088855954842)

=$842.13  ( answer )

4 0
3 years ago
Read 2 more answers
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