Given:
side length = 6 ft
To find:
The area of the figure
Solution:
Area of the square = side × side
= 6 × 6
Area of the square = 36 ft²
Diameter of the semi-circle = 6 ft
Radius of the semi-circle = 6 ÷ 2 = 3 ft
Area of the semi-circle =
Area of the semi-circle = 14.13 ft²
Area of the figure = Area of the square - Area of the semi-circle
= 36 ft² - 14.13 ft²
= 21.87 ft²
Area of the figure = 21.9 ft²
The area of the figure is 21.9 ft².
Answer:
The z-score for SAT exam of junior is much small than his ACT score. This means he performed well in his ACT exam and performed poor in his SAT exam.
Step-by-step explanation:
Mean SAT scores = 1026
Standard Deviation = 209
Mean ACT score = 20.8
Standard Deviation = 4.8
We are given SAT and ACT scores of a student and we have to compare them. We cannot compare them directly so we have to Normalize them i.e. convert them into such a form that we can compare the numbers in a meaningful manner. The best way out is to convert both the values into their equivalent z-scores and then do the comparison. Comparison of equivalent z-scores will tell us which score is higher and which is lower.
The formula to calculate the z-score is:
Here, μ is the mean and σ is the standard deviation. x is the value we want to convert to z score.
z-score for junior scoring 860 in SAT exam will be:
z-score for junior scoring 16 in ACT exam will be:
The z-score for SAT exam of junior is much small than his ACT score. This means he performed well in his ACT exam and performed poor in his SAT exam.